标签：std int ll system 一本 通刷题 txt define
一本通
BFS part
1
http://ybt.ssoier.cn:8088/problem_show.php?pid=1329
一道基础的求连通块的题目
点击查看代码
#include<bits/stdc++.h>
#define rep(i,l,r) for(int i=int(l);i<int(r);i++)
#define per(i,r,l) for(int i=int(r-1);i>=int(l);i--)
#define repg(i,l,r) for(i=int(l);i<int(r);i++)
#define perg(i,r,l) for(int i=int(r-1);i>=int(l);i--)
#define rept(i,t) for(int i=int(h[t]);~i;i=ne[i])
#define reph(i,t,h) for(int i=int(h[t]);~i;i=ne[i])
#define x first
#define y second
#define pb push_back
#define pf push_front
#define ppb pop_back
#define ppf pop_front
#define all(x) (x).begin(),(x).end()
using namespace std;
typedef long long ll;
typedef unsigned long long lll;
typedef pair<int,int> PII;
typedef pair<double,double> PDD;
const int INF=0x3f3f3f3f,mod=1e9+7;
const ll INFF=1e18;
const double eps=1e-9;
mt19937 mrand(random_device{}());
template<class A, class B> ostream& operator <<(ostream& out, const pair<A, B> &p) {
return out << "(" << p.x << " " << p.y << ")";
}
template<class A> ostream& operator <<(ostream& out, const vector<A> &v) {
rep(i, 0, sz(v)) {
if(i) out << " ";
out << v[i];
}
return out;
}
int rnd(int x){return mrand()%x;}
ll qmi(ll a,ll b){ll res=1;a%=mod;while(b){if(b&1)res=res*a%mod;a=a*a%mod;b>>=1;}return res;}
ll qmul(ll a,ll b){ll res=0;a%=mod;while(b){if(b&1) res=(res+a)%mod;a=(a+a)%mod;b>>=1;} return res;}
ll gcd(ll a,ll b){return b?gcd(b,a%b):a;}
/*ll read()
{
ll x=0,f=1;char c=getchar();
while(c<'0'||c>'9'){if(c=='-')f=-1;c=getchar();}
while(c>='0'&&c<='9')x=x*10+(c-'0'),c=getchar();
return f*x;
}*/
//#include <iostream>
//#include <cstdio>
//#include <windows.h>
//#include <cstdlib>
//#include <ctime>
//using namespace std;
//int main()
//{
// int ok = 0;
// int n = 50;
// for (int i = 1; i <= n; ++i)
// {
// system("make.exe > make.txt");
// system("std.exe < make.txt > std.txt");
// double begin = clock();
// system("baoli.exe < make.txt > baoli.txt");
// double end = clock();
//
// double t = (end - begin);
// if (system("fc std.txt baoli.txt"))
// {
// printf("测试点#%d Wrong Answer\n", i);
// }
// else if (t > 1000) //1秒
// {
// printf("测试点#%d Time Limited Exceeded 用时 %.0lfms\n", i, t);
// }
// else
// {
// printf("测试点#%d Accepted 用时%.0lfms\n", i, t);
// ok++; //AC数量+1
// }
// }
// printf("\n");
// double res = 100.0 * ok / n;
// printf("共 %d 组测试数据，AC数据 %d 组。 得分%.1lf。", n, ok, res);
//
// Sleep(1000); //休眠1秒，为了节约对拍次数。
//}
inline int read()
{
int x=0;
char ch;
bool fx=false;
do ch=getchar();while(~ch&&ch!='-'&&(ch<48||ch>57));
if(ch=='-')fx=true,ch=getchar();
for(;ch>47&&ch<58;ch=getchar())
x=(x<<1)+(x<<3)+(ch^48);
return fx?-x:x;
}
const int N=1e3+52;
int n,m,ans;
bool st[N][N];
int d[4][2]={{1,0},{0,-1},{0,1},{-1,0}};
char g[N][N];
PII point[N*N];
void bfs(int sx,int sy)
{
int hh=0,tt=0;
point[0]={sx,sy};
st[sx][sy]=1;
while(hh<=tt)
{
PII t=point[hh++];
rep(i,0,4)
rep(j,0,2)
{
int x1=t.x+d[i][0],y1=t.y+d[i][1];
if(x1==t.x&&y1==t.y) continue;
if(x1<0||x1>=n||y1<0||y1>=m) continue;
if(g[x1][y1]=='0'||st[x1][y1]) continue;
point[++tt]={x1,y1};
st[x1][y1]=1;
}
}
}
int main()
{
#ifdef my_test
freopen(".in","r",stdin);
freopen(".out","w",stdout);
#endif
#ifdef my_dp
while(1)
{
system("data.exe > in.txt");
system("brute.exe < in.txt > brute.txt");
system("std.exe < in.txt > std.txt");
if(system("fc std.txt brute.txt"))
break;
}
#endif
#ifdef my_dp2
while (1) //一直循环，直到找到不一样的数据
{
system("data.exe");
system("baoli.exe");
system("std.exe");
if (system("fc std.txt baoli.txt")) //当 fc 返回1时，说明这时数据不一样
break; //不一样就跳出循环
}
#endif
clock_t start,end;
start=clock();
n=read(),m=read();
rep(i,0,n) scanf("%s",g[i]);
rep(i,0,n)
{
rep(j,0,m)
if(g[i][j]!='0'&&!st[i][j])
{
bfs(i,j);
ans++;
}
}
printf("%d\n",ans);
end=clock();
// printf("%lfms\n",(double)(end-start)/CLOCKS_PER_SEC*1000);
return 0;
}
http://ybt.ssoier.cn:8088/problem_show.php?pid=1249
floodfill计算连通块模型
点击查看代码
#include<bits/stdc++.h>
#define rep(i,l,r) for(int i=int(l);i<int(r);i++)
#define per(i,r,l) for(int i=int(r-1);i>=int(l);i--)
#define repg(i,l,r) for(i=int(l);i<int(r);i++)
#define perg(i,r,l) for(int i=int(r-1);i>=int(l);i--)
#define rept(i,t) for(int i=int(h[t]);~i;i=ne[i])
#define reph(i,t,h) for(int i=int(h[t]);~i;i=ne[i])
#define x first
#define y second
#define pb push_back
#define pf push_front
#define ppb pop_back
#define ppf pop_front
#define all(x) (x).begin(),(x).end()
using namespace std;
typedef long long ll;
typedef unsigned long long lll;
typedef pair<int,int> PII;
typedef pair<double,double> PDD;
const int INF=0x3f3f3f3f,mod=1e9+7;
const ll INFF=1e18;
const double eps=1e-9;
mt19937 mrand(random_device{}());
template<class A, class B> ostream& operator <<(ostream& out, const pair<A, B> &p) {
return out << "(" << p.x << " " << p.y << ")";
}
template<class A> ostream& operator <<(ostream& out, const vector<A> &v) {
rep(i, 0, sz(v)) {
if(i) out << " ";
out << v[i];
}
return out;
}
int rnd(int x){return mrand()%x;}
ll qmi(ll a,ll b){ll res=1;a%=mod;while(b){if(b&1)res=res*a%mod;a=a*a%mod;b>>=1;}return res;}
ll qmul(ll a,ll b){ll res=0;a%=mod;while(b){if(b&1) res=(res+a)%mod;a=(a+a)%mod;b>>=1;} return res;}
ll gcd(ll a,ll b){return b?gcd(b,a%b):a;}
/*ll read()
{
ll x=0,f=1;char c=getchar();
while(c<'0'||c>'9'){if(c=='-')f=-1;c=getchar();}
while(c>='0'&&c<='9')x=x*10+(c-'0'),c=getchar();
return f*x;
}*/
//#include <iostream>
//#include <cstdio>
//#include <windows.h>
//#include <cstdlib>
//#include <ctime>
//using namespace std;
//int main()
//{
// int ok = 0;
// int n = 50;
// for (int i = 1; i <= n; ++i)
// {
// system("make.exe > make.txt");
// system("std.exe < make.txt > std.txt");
// double begin = clock();
// system("baoli.exe < make.txt > baoli.txt");
// double end = clock();
//
// double t = (end - begin);
// if (system("fc std.txt baoli.txt"))
// {
// printf("测试点#%d Wrong Answer\n", i);
// }
// else if (t > 1000) //1秒
// {
// printf("测试点#%d Time Limited Exceeded 用时 %.0lfms\n", i, t);
// }
// else
// {
// printf("测试点#%d Accepted 用时%.0lfms\n", i, t);
// ok++; //AC数量+1
// }
// }
// printf("\n");
// double res = 100.0 * ok / n;
// printf("共 %d 组测试数据，AC数据 %d 组。 得分%.1lf。", n, ok, res);
//
// Sleep(1000); //休眠1秒，为了节约对拍次数。
//}
inline int read()
{
int x=0;
char ch;
bool fx=false;
do ch=getchar();while(~ch&&ch!='-'&&(ch<48||ch>57));
if(ch=='-')fx=true,ch=getchar();
for(;ch>47&&ch<58;ch=getchar())
x=(x<<1)+(x<<3)+(ch^48);
return fx?-x:x;
}
const int N=520;
int n,m,ans;
char g[N][N];
int q[N];
bool st[N][N];
PII point[N*N];
void bfs(int sx,int sy)
{
int hh=0,tt=0;
point[0]={sx,sy};
st[sx][sy] =1;
while(hh<=tt)
{
PII t=point[hh++];
rep(i,t.x-1,t.x+2)
rep(j,t.y-1,t.y+2)
{
if(i==t.x&&j==t.y) continue;
if(i<0||i>=n||j<0||j>=m) continue;
if(g[i][j]=='.'||st[i][j]) continue;
point[++tt]={i,j};
st[i][j]=1;
}
}
}
int main()
{
#ifdef my_test
freopen(".in","r",stdin);
freopen(".out","w",stdout);
#endif
#ifdef my_dp
while(1)
{
system("data.exe > in.txt");
system("brute.exe < in.txt > brute.txt");
system("std.exe < in.txt > std.txt");
if(system("fc std.txt brute.txt"))
break;
}
#endif
#ifdef my_dp2
while (1) //一直循环，直到找到不一样的数据
{
system("data.exe");
system("baoli.exe");
system("std.exe");
if (system("fc std.txt baoli.txt")) //当 fc 返回1时，说明这时数据不一样
break; //不一样就跳出循环
}
#endif
clock_t start,end;
start=clock();
n=read(),m=read();
rep(i,0,n) scanf("%s",g[i]);
rep(i,0,n)
rep(j,0,m)
if(!st[i][j]&&g[i][j]=='W')bfs(i,j),ans++;
printf("%d\n",ans);
end=clock();
// printf("%lfms\n",(double)(end-start)/CLOCKS_PER_SEC*1000);
return 0;
}
http://ybt.ssoier.cn:8088/problem_show.php?pid=1250
floodfill
点击查看代码
#include<bits/stdc++.h>
#define rep(i,l,r) for(int i=int(l);i<int(r);i++)
#define per(i,r,l) for(int i=int(r-1);i>=int(l);i--)
#define repg(i,l,r) for(i=int(l);i<int(r);i++)
#define perg(i,r,l) for(int i=int(r-1);i>=int(l);i--)
#define rept(i,t) for(int i=int(h[t]);~i;i=ne[i])
#define reph(i,t,h) for(int i=int(h[t]);~i;i=ne[i])
#define x first
#define y second
#define pb push_back
#define pf push_front
#define ppb pop_back
#define ppf pop_front
#define all(x) (x).begin(),(x).end()
using namespace std;
typedef long long ll;
typedef unsigned long long lll;
typedef pair<int,int> PII;
typedef pair<double,double> PDD;
const int INF=0x3f3f3f3f,mod=1e9+7;
const ll INFF=1e18;
const double eps=1e-9;
mt19937 mrand(random_device{}());
template<class A, class B> ostream& operator <<(ostream& out, const pair<A, B> &p) {
return out << "(" << p.x << " " << p.y << ")";
}
template<class A> ostream& operator <<(ostream& out, const vector<A> &v) {
rep(i, 0, sz(v)) {
if(i) out << " ";
out << v[i];
}
return out;
}
int rnd(int x){return mrand()%x;}
ll qmi(ll a,ll b){ll res=1;a%=mod;while(b){if(b&1)res=res*a%mod;a=a*a%mod;b>>=1;}return res;}
ll qmul(ll a,ll b){ll res=0;a%=mod;while(b){if(b&1) res=(res+a)%mod;a=(a+a)%mod;b>>=1;} return res;}
ll gcd(ll a,ll b){return b?gcd(b,a%b):a;}
/*ll read()
{
ll x=0,f=1;char c=getchar();
while(c<'0'||c>'9'){if(c=='-')f=-1;c=getchar();}
while(c>='0'&&c<='9')x=x*10+(c-'0'),c=getchar();
return f*x;
}*/
//#include <iostream>
//#include <cstdio>
//#include <windows.h>
//#include <cstdlib>
//#include <ctime>
//using namespace std;
//int main()
//{
// int ok = 0;
// int n = 50;
// for (int i = 1; i <= n; ++i)
// {
// system("make.exe > make.txt");
// system("std.exe < make.txt > std.txt");
// double begin = clock();
// system("baoli.exe < make.txt > baoli.txt");
// double end = clock();
//
// double t = (end - begin);
// if (system("fc std.txt baoli.txt"))
// {
// printf("测试点#%d Wrong Answer\n", i);
// }
// else if (t > 1000) //1秒
// {
// printf("测试点#%d Time Limited Exceeded 用时 %.0lfms\n", i, t);
// }
// else
// {
// printf("测试点#%d Accepted 用时%.0lfms\n", i, t);
// ok++; //AC数量+1
// }
// }
// printf("\n");
// double res = 100.0 * ok / n;
// printf("共 %d 组测试数据，AC数据 %d 组。 得分%.1lf。", n, ok, res);
//
// Sleep(1000); //休眠1秒，为了节约对拍次数。
//}
inline int read()
{
int x=0;
char ch;
bool fx=false;
do ch=getchar();while(~ch&&ch!='-'&&(ch<48||ch>57));
if(ch=='-')fx=true,ch=getchar();
for(;ch>47&&ch<58;ch=getchar())
x=(x<<1)+(x<<3)+(ch^48);
return fx?-x:x;
}
const int N=52;
int n,m;
int g[N][N];
bool st[N][N];
PII q[N*N];
int bfs(int sx,int sy)
{
int d[4][2]={{0,-1},{-1,0},{0,1},{1,0}};
int hh=0,tt=0;q[0]={sx,sy};
st[sx][sy]=1;
int area=0;
while(hh<=tt)
{
PII t=q[hh++];
area++;
rep(i,0,4)
{
int a=t.x+d[i][0],b=t.y+d[i][1];
if(a<0||a>=n||b<0||b>=m) continue;
if(st[a][b]) continue;
if(g[t.x][t.y]>>i&1) continue;
q[++tt]={a,b};
st[a][b]=1;
}
}
return area;
}
int main()
{
#ifdef my_test
freopen(".in","r",stdin);
freopen(".out","w",stdout);
#endif
#ifdef my_dp
while(1)
{
system("data.exe > in.txt");
system("brute.exe < in.txt > brute.txt");
system("std.exe < in.txt > std.txt");
if(system("fc std.txt brute.txt"))
break;
}
#endif
#ifdef my_dp2
while (1) //一直循环，直到找到不一样的数据
{
system("data.exe");
system("baoli.exe");
system("std.exe");
if (system("fc std.txt baoli.txt")) //当 fc 返回1时，说明这时数据不一样
break; //不一样就跳出循环
}
#endif
clock_t start,end;
start=clock();
n=read(),m=read();
rep(i,0,n) rep(j,0,m) g[i][j]=read();
int cnt=0,area=0;
rep(i,0,n) rep(j,0,m) if(!st[i][j]) area=max(area,bfs(i,j)),cnt++;
printf("%d\n%d\n",cnt,area);
end=clock();
// printf("%lfms\n",(double)(end-start)/CLOCKS_PER_SEC*1000);
return 0;
}
http://ybt.ssoier.cn:8088/problem_show.php?pid=1251
bfs求最短路
点击查看代码
#include<bits/stdc++.h>
#define rep(i,l,r) for(int i=int(l);i<int(r);i++)
#define per(i,r,l) for(int i=int(r-1);i>=int(l);i--)
#define repg(i,l,r) for(i=int(l);i<int(r);i++)
#define perg(i,r,l) for(int i=int(r-1);i>=int(l);i--)
#define rept(i,t) for(int i=int(h[t]);~i;i=ne[i])
#define reph(i,t,h) for(int i=int(h[t]);~i;i=ne[i])
#define x first
#define y second
#define pb push_back
#define pf push_front
#define ppb pop_back
#define ppf pop_front
#define all(x) (x).begin(),(x).end()
using namespace std;
typedef long long ll;
typedef unsigned long long lll;
typedef pair<int,int> PII;
typedef pair<double,double> PDD;
const int INF=0x3f3f3f3f,mod=1e9+7;
const ll INFF=1e18;
const double eps=1e-9;
mt19937 mrand(random_device{}());
template<class A, class B> ostream& operator <<(ostream& out, const pair<A, B> &p) {
return out << "(" << p.x << " " << p.y << ")";
}
template<class A> ostream& operator <<(ostream& out, const vector<A> &v) {
rep(i, 0, sz(v)) {
if(i) out << " ";
out << v[i];
}
return out;
}
int rnd(int x){return mrand()%x;}
ll qmi(ll a,ll b){ll res=1;a%=mod;while(b){if(b&1)res=res*a%mod;a=a*a%mod;b>>=1;}return res;}
ll qmul(ll a,ll b){ll res=0;a%=mod;while(b){if(b&1) res=(res+a)%mod;a=(a+a)%mod;b>>=1;} return res;}
ll gcd(ll a,ll b){return b?gcd(b,a%b):a;}
/*ll read()
{
ll x=0,f=1;char c=getchar();
while(c<'0'||c>'9'){if(c=='-')f=-1;c=getchar();}
while(c>='0'&&c<='9')x=x*10+(c-'0'),c=getchar();
return f*x;
}*/
//#include <iostream>
//#include <cstdio>
//#include <windows.h>
//#include <cstdlib>
//#include <ctime>
//using namespace std;
//int main()
//{
// int ok = 0;
// int n = 50;
// for (int i = 1; i <= n; ++i)
// {
// system("make.exe > make.txt");
// system("std.exe < make.txt > std.txt");
// double begin = clock();
// system("baoli.exe < make.txt > baoli.txt");
// double end = clock();
//
// double t = (end - begin);
// if (system("fc std.txt baoli.txt"))
// {
// printf("测试点#%d Wrong Answer\n", i);
// }
// else if (t > 1000) //1秒
// {
// printf("测试点#%d Time Limited Exceeded 用时 %.0lfms\n", i, t);
// }
// else
// {
// printf("测试点#%d Accepted 用时%.0lfms\n", i, t);
// ok++; //AC数量+1
// }
// }
// printf("\n");
// double res = 100.0 * ok / n;
// printf("共 %d 组测试数据，AC数据 %d 组。 得分%.1lf。", n, ok, res);
//
// Sleep(1000); //休眠1秒，为了节约对拍次数。
//}
inline int read()
{
int x=0;
char ch;
bool fx=false;
do ch=getchar();while(~ch&&ch!='-'&&(ch<48||ch>57));
if(ch=='-')fx=true,ch=getchar();
for(;ch>47&&ch<58;ch=getchar())
x=(x<<1)+(x<<3)+(ch^48);
return fx?-x:x;
}
const int N=52;
int n,m,cnt;
int sx,sy;
PII q[N*N];
char g[N][N];
int dis[N][N];//不需要d因为走过就有了距离
int d[4][2]={{1,0},{0,1},{-1,0},{0,-1}};
int bfs(int sx,int sy)
{
q[0]={sx,sy};
memset(dis,-1,sizeof(dis));
dis[sx][sy]=0;
int hh=0,tt=0;
while(hh<=tt)
{
PII t=q[hh++];
rep(i,0,4)
{
int a=t.x+d[i][0],b=t.y+d[i][1];
if(a<0||b<0||a>=n||b>=m) continue;
if(dis[a][b]!=-1||g[a][b]=='#') continue;
dis[a][b]=dis[t.x][t.y]+1;
if(g[a][b]=='*') return dis[a][b];
q[++tt]={a,b};
}
}
return -1;
}
int main()
{
#ifdef my_test
freopen(".in","r",stdin);
freopen(".out","w",stdout);
#endif
#ifdef my_dp
while(1)
{
system("data.exe > in.txt");
system("brute.exe < in.txt > brute.txt");
system("std.exe < in.txt > std.txt");
if(system("fc std.txt brute.txt"))
break;
}
#endif
#ifdef my_dp2
while (1) //一直循环，直到找到不一样的数据
{
system("data.exe");
system("baoli.exe");
system("std.exe");
if (system("fc std.txt baoli.txt")) //当 fc 返回1时，说明这时数据不一样
break; //不一样就跳出循环
}
#endif
clock_t start,end;
start=clock();
while(cin >> n >> m, n || m)
{
for(int i = 0; i < n; i ++) cin >> g[i];
for(int i = 0; i < n; i ++)
// for(int j = 0; j < n; j ++) // **3
for(int j = 0; j < m; j ++)
if(g[i][j] == '@')
sx=i,sy=j;
cout << bfs(sx,sy) << endl;
}
end=clock();
// printf("%lfms\n",(double)(end-start)/CLOCKS_PER_SEC*1000);
return 0;
}
http://ybt.ssoier.cn:8088/problem_show.php?pid=1252
bfs求最短路
点击查看代码
#include<bits/stdc++.h>
#define rep(i,l,r) for(int i=int(l);i<int(r);i++)
#define per(i,r,l) for(int i=int(r-1);i>=int(l);i--)
#define repg(i,l,r) for(i=int(l);i<int(r);i++)
#define perg(i,r,l) for(int i=int(r-1);i>=int(l);i--)
#define rept(i,t) for(int i=int(h[t]);~i;i=ne[i])
#define reph(i,t,h) for(int i=int(h[t]);~i;i=ne[i])
#define x first
#define y second
#define pb push_back
#define pf push_front
#define ppb pop_back
#define ppf pop_front
#define all(x) (x).begin(),(x).end()
using namespace std;
typedef long long ll;
typedef unsigned long long lll;
typedef pair<int,int> PII;
typedef pair<double,double> PDD;
const int INF=0x3f3f3f3f,mod=1e9+7;
const ll INFF=1e18;
const double eps=1e-9;
mt19937 mrand(random_device{}());
template<class A, class B> ostream& operator <<(ostream& out, const pair<A, B> &p) {
return out << "(" << p.x << " " << p.y << ")";
}
template<class A> ostream& operator <<(ostream& out, const vector<A> &v) {
rep(i, 0, sz(v)) {
if(i) out << " ";
out << v[i];
}
return out;
}
int rnd(int x){return mrand()%x;}
ll qmi(ll a,ll b){ll res=1;a%=mod;while(b){if(b&1)res=res*a%mod;a=a*a%mod;b>>=1;}return res;}
ll qmul(ll a,ll b){ll res=0;a%=mod;while(b){if(b&1) res=(res+a)%mod;a=(a+a)%mod;b>>=1;} return res;}
ll gcd(ll a,ll b){return b?gcd(b,a%b):a;}
/*ll read()
{
ll x=0,f=1;char c=getchar();
while(c<'0'||c>'9'){if(c=='-')f=-1;c=getchar();}
while(c>='0'&&c<='9')x=x*10+(c-'0'),c=getchar();
return f*x;
}*/
//#include <iostream>
//#include <cstdio>
//#include <windows.h>
//#include <cstdlib>
//#include <ctime>
//using namespace std;
//int main()
//{
// int ok = 0;
// int n = 50;
// for (int i = 1; i <= n; ++i)
// {
// system("make.exe > make.txt");
// system("std.exe < make.txt > std.txt");
// double begin = clock();
// system("baoli.exe < make.txt > baoli.txt");
// double end = clock();
//
// double t = (end - begin);
// if (system("fc std.txt baoli.txt"))
// {
// printf("测试点#%d Wrong Answer\n", i);
// }
// else if (t > 1000) //1秒
// {
// printf("测试点#%d Time Limited Exceeded 用时 %.0lfms\n", i, t);
// }
// else
// {
// printf("测试点#%d Accepted 用时%.0lfms\n", i, t);
// ok++; //AC数量+1
// }
// }
// printf("\n");
// double res = 100.0 * ok / n;
// printf("共 %d 组测试数据，AC数据 %d 组。 得分%.1lf。", n, ok, res);
//
// Sleep(1000); //休眠1秒，为了节约对拍次数。
//}
inline int read()
{
int x=0;
char ch;
bool fx=false;
do ch=getchar();while(~ch&&ch!='-'&&(ch<48||ch>57));
if(ch=='-')fx=true,ch=getchar();
for(;ch>47&&ch<58;ch=getchar())
x=(x<<1)+(x<<3)+(ch^48);
return fx?-x:x;
}
const int N=52;
int n,m;
char g[N][N];
PII q[N*N];
int dist[N][N];
int d[4][2]={{1,0},{0,1},{-1,0},{0,-1}};
int bfs(int sx,int sy)
{
memset(dist,-1,sizeof(dist));
int hh=0,tt=0;
q[0]={sx,sy};
dist[sx][sy]=1;
while(hh<=tt)
{
PII t=q[hh++];
rep(i,0,4)
{
int a=t.x+d[i][0],b=t.y+d[i][1];
if(a<0||a>=n||b<0||b>=m) continue;
if(dist[a][b]!=-1||g[a][b]=='#') continue;
dist[a][b]=dist[t.x][t.y]+1;q[++tt]={a,b};
}
}
return dist[n-1][m-1];
}
int main()
{
#ifdef my_test
freopen(".in","r",stdin);
freopen(".out","w",stdout);
#endif
#ifdef my_dp
while(1)
{
system("data.exe > in.txt");
system("brute.exe < in.txt > brute.txt");
system("std.exe < in.txt > std.txt");
if(system("fc std.txt brute.txt"))
break;
}
#endif
#ifdef my_dp2
while (1) //一直循环，直到找到不一样的数据
{
system("data.exe");
system("baoli.exe");
system("std.exe");
if (system("fc std.txt baoli.txt")) //当 fc 返回1时，说明这时数据不一样
break; //不一样就跳出循环
}
#endif
clock_t start,end;
start=clock();
n=read(),m=read();
rep(i,0,n) scanf("%s",g[i]);
printf("%d\n",bfs(0,0));
end=clock();
// printf("%lfms\n",(double)(end-start)/CLOCKS_PER_SEC*1000);
return 0;
}
http://ybt.ssoier.cn:8088/problem_show.php?pid=1254
bfs最短路
点击查看代码
#include<bits/stdc++.h>
#define rep(i,l,r) for(int i=int(l);i<int(r);i++)
#define per(i,r,l) for(int i=int(r-1);i>=int(l);i--)
#define repg(i,l,r) for(i=int(l);i<int(r);i++)
#define perg(i,r,l) for(int i=int(r-1);i>=int(l);i--)
#define rept(i,t) for(int i=int(h[t]);~i;i=ne[i])
#define reph(i,t,h) for(int i=int(h[t]);~i;i=ne[i])
#define x first
#define y second
#define pb push_back
#define pf push_front
#define ppb pop_back
#define ppf pop_front
#define all(x) (x).begin(),(x).end()
using namespace std;
typedef long long ll;
typedef unsigned long long lll;
typedef pair<int,int> PII;
typedef pair<double,double> PDD;
const int INF=0x3f3f3f3f,mod=1e9+7;
const ll INFF=1e18;
const double eps=1e-9;
mt19937 mrand(random_device{}());
template<class A, class B> ostream& operator <<(ostream& out, const pair<A, B> &p) {
return out << "(" << p.x << " " << p.y << ")";
}
template<class A> ostream& operator <<(ostream& out, const vector<A> &v) {
rep(i, 0, sz(v)) {
if(i) out << " ";
out << v[i];
}
return out;
}
int rnd(int x){return mrand()%x;}
ll qmi(ll a,ll b){ll res=1;a%=mod;while(b){if(b&1)res=res*a%mod;a=a*a%mod;b>>=1;}return res;}
ll qmul(ll a,ll b){ll res=0;a%=mod;while(b){if(b&1) res=(res+a)%mod;a=(a+a)%mod;b>>=1;} return res;}
ll gcd(ll a,ll b){return b?gcd(b,a%b):a;}
/*ll read()
{
ll x=0,f=1;char c=getchar();
while(c<'0'||c>'9'){if(c=='-')f=-1;c=getchar();}
while(c>='0'&&c<='9')x=x*10+(c-'0'),c=getchar();
return f*x;
}*/
//#include <iostream>
//#include <cstdio>
//#include <windows.h>
//#include <cstdlib>
//#include <ctime>
//using namespace std;
//int main()
//{
// int ok = 0;
// int n = 50;
// for (int i = 1; i <= n; ++i)
// {
// system("make.exe > make.txt");
// system("std.exe < make.txt > std.txt");
// double begin = clock();
// system("baoli.exe < make.txt > baoli.txt");
// double end = clock();
//
// double t = (end - begin);
// if (system("fc std.txt baoli.txt"))
// {
// printf("测试点#%d Wrong Answer\n", i);
// }
// else if (t > 1000) //1秒
// {
// printf("测试点#%d Time Limited Exceeded 用时 %.0lfms\n", i, t);
// }
// else
// {
// printf("测试点#%d Accepted 用时%.0lfms\n", i, t);
// ok++; //AC数量+1
// }
// }
// printf("\n");
// double res = 100.0 * ok / n;
// printf("共 %d 组测试数据，AC数据 %d 组。 得分%.1lf。", n, ok, res);
//
// Sleep(1000); //休眠1秒，为了节约对拍次数。
//}
inline int read()
{
int x=0;
char ch;
bool fx=false;
do ch=getchar();while(~ch&&ch!='-'&&(ch<48||ch>57));
if(ch=='-')fx=true,ch=getchar();
for(;ch>47&&ch<58;ch=getchar())
x=(x<<1)+(x<<3)+(ch^48);
return fx?-x:x;
}
const int N=520;
int n,m;
char g[N][N];
int dist[N][N];
PII q[N*N];
int d[4][2]={{1,0},{0,1},{-1,0},{0,-1}};
int sx,sy;
int bfs(int sx,int sy){
memset(dist,-1,sizeof(dist));
int hh=0,tt=0;
dist[sx][sy]=0;
q[0]={sx,sy};
while(hh<=tt)
{
PII t=q[hh++];
rep(i,0,4)
{
int a=t.x+d[i][0],b=t.y+d[i][1];
if(a<0||a>=n||b<0||b>=m) continue;
if(g[a][b]=='#'||dist[a][b]!=-1) continue;
dist[a][b]=dist[t.x][t.y]+1;q[++tt]={a,b};
if(g[a][b]=='T') return dist[a][b];
}
}
}
int main()
{
#ifdef my_test
freopen(".in","r",stdin);
freopen(".out","w",stdout);
#endif
#ifdef my_dp
while(1)
{
system("data.exe > in.txt");
system("brute.exe < in.txt > brute.txt");
system("std.exe < in.txt > std.txt");
if(system("fc std.txt brute.txt"))
break;
}
#endif
#ifdef my_dp2
while (1) //一直循环，直到找到不一样的数据
{
system("data.exe");
system("baoli.exe");
system("std.exe");
if (system("fc std.txt baoli.txt")) //当 fc 返回1时，说明这时数据不一样
break; //不一样就跳出循环
}
#endif
clock_t start,end;
start=clock();
n=read(),m=read();
rep(i,0,n) scanf("%s",g[i]);
rep(i,0,n)
rep(j,0,m)
if(g[i][j]=='S') sx=i,sy=j;
printf("%d\n",bfs(sx,sy));
end=clock();
// printf("%lfms\n",(double)(end-start)/CLOCKS_PER_SEC*1000);
return 0;
}
http://ybt.ssoier.cn:8088/problem_show.php?pid=1256
bfs求最短路
点击查看代码
#include<bits/stdc++.h>
#define rep(i,l,r) for(int i=int(l);i<int(r);i++)
#define per(i,r,l) for(int i=int(r-1);i>=int(l);i--)
#define repg(i,l,r) for(i=int(l);i<int(r);i++)
#define perg(i,r,l) for(int i=int(r-1);i>=int(l);i--)
#define rept(i,t) for(int i=int(h[t]);~i;i=ne[i])
#define reph(i,t,h) for(int i=int(h[t]);~i;i=ne[i])
#define x first
#define y second
#define pb push_back
#define pf push_front
#define ppb pop_back
#define ppf pop_front
#define all(x) (x).begin(),(x).end()
using namespace std;
typedef long long ll;
typedef unsigned long long lll;
typedef pair<int,int> PII;
typedef pair<double,double> PDD;
const int INF=0x3f3f3f3f,mod=1e9+7;
const ll INFF=1e18;
const double eps=1e-9;
mt19937 mrand(random_device{}());
template<class A, class B> ostream& operator <<(ostream& out, const pair<A, B> &p) {
return out << "(" << p.x << " " << p.y << ")";
}
template<class A> ostream& operator <<(ostream& out, const vector<A> &v) {
rep(i, 0, sz(v)) {
if(i) out << " ";
out << v[i];
}
return out;
}
int rnd(int x){return mrand()%x;}
ll qmi(ll a,ll b){ll res=1;a%=mod;while(b){if(b&1)res=res*a%mod;a=a*a%mod;b>>=1;}return res;}
ll qmul(ll a,ll b){ll res=0;a%=mod;while(b){if(b&1) res=(res+a)%mod;a=(a+a)%mod;b>>=1;} return res;}
ll gcd(ll a,ll b){return b?gcd(b,a%b):a;}
/*ll read()
{
ll x=0,f=1;char c=getchar();
while(c<'0'||c>'9'){if(c=='-')f=-1;c=getchar();}
while(c>='0'&&c<='9')x=x*10+(c-'0'),c=getchar();
return f*x;
}*/
//#include <iostream>
//#include <cstdio>
//#include <windows.h>
//#include <cstdlib>
//#include <ctime>
//using namespace std;
//int main()
//{
// int ok = 0;
// int n = 50;
// for (int i = 1; i <= n; ++i)
// {
// system("make.exe > make.txt");
// system("std.exe < make.txt > std.txt");
// double begin = clock();
// system("baoli.exe < make.txt > baoli.txt");
// double end = clock();
//
// double t = (end - begin);
// if (system("fc std.txt baoli.txt"))
// {
// printf("测试点#%d Wrong Answer\n", i);
// }
// else if (t > 1000) //1秒
// {
// printf("测试点#%d Time Limited Exceeded 用时 %.0lfms\n", i, t);
// }
// else
// {
// printf("测试点#%d Accepted 用时%.0lfms\n", i, t);
// ok++; //AC数量+1
// }
// }
// printf("\n");
// double res = 100.0 * ok / n;
// printf("共 %d 组测试数据，AC数据 %d 组。 得分%.1lf。", n, ok, res);
//
// Sleep(1000); //休眠1秒，为了节约对拍次数。
//}
inline int read()
{
int x=0;
char ch;
bool fx=false;
do ch=getchar();while(~ch&&ch!='-'&&(ch<48||ch>57));
if(ch=='-')fx=true,ch=getchar();
for(;ch>47&&ch<58;ch=getchar())
x=(x<<1)+(x<<3)+(ch^48);
return fx?-x:x;
}
const int N=520;
int n,m,t;
char g[N][N];
PII q[N*N];
int dist[N][N];
int sx,sy;
int d[4][2]={{1,0},{-1,0},{0,1},{0,-1}};
int bfs(int sx,int sy)
{
memset(dist,-1,sizeof(dist));
int hh=0,tt=0;
q[0]={sx,sy};
dist[sx][sy]=0;
while(hh<=tt)
{
PII t=q[hh++];
rep(i,0,4)
{
int a=t.x+d[i][0],b=t.y+d[i][1];
if(a<0||a>=n||b<0||b>=m) continue;
if(g[a][b]=='#'||dist[a][b]!=-1) continue;
dist[a][b]=dist[t.x][t.y]+1,q[++tt]={a,b};
if(g[a][b]=='E') return dist[a][b];
}
}
return -1;
}
int main()
{
#ifdef my_test
freopen(".in","r",stdin);
freopen(".out","w",stdout);
#endif
#ifdef my_dp
while(1)
{
system("data.exe > in.txt");
system("brute.exe < in.txt > brute.txt");
system("std.exe < in.txt > std.txt");
if(system("fc std.txt brute.txt"))
break;
}
#endif
#ifdef my_dp2
while (1) //一直循环，直到找到不一样的数据
{
system("data.exe");
system("baoli.exe");
system("std.exe");
if (system("fc std.txt baoli.txt")) //当 fc 返回1时，说明这时数据不一样
break; //不一样就跳出循环
}
#endif
clock_t start,end;
start=clock();
t=read();
while(t--)
{
n=read(),m=read();
rep(i,0,n) scanf("%s",g[i]);
rep(i,0,n) rep(j,0,m) if(g[i][j]=='S') sx=i,sy=j;
int ans=bfs(sx,sy);
if(ans==-1) puts("oop!");
else printf("%d\n",ans);
}
end=clock();
// printf("%lfms\n",(double)(end-start)/CLOCKS_PER_SEC*1000);
return 0;
}
http://ybt.ssoier.cn:8088/problem_show.php?pid=1257
bfs求最短路，日字路径，
点击查看代码
#include<bits/stdc++.h>
#define rep(i,l,r) for(int i=int(l);i<int(r);i++)
#define per(i,r,l) for(int i=int(r-1);i>=int(l);i--)
#define repg(i,l,r) for(i=int(l);i<int(r);i++)
#define perg(i,r,l) for(int i=int(r-1);i>=int(l);i--)
#define rept(i,t) for(int i=int(h[t]);~i;i=ne[i])
#define reph(i,t,h) for(int i=int(h[t]);~i;i=ne[i])
#define x first
#define y second
#define pb push_back
#define pf push_front
#define ppb pop_back
#define ppf pop_front
#define all(x) (x).begin(),(x).end()
using namespace std;
typedef long long ll;
typedef unsigned long long lll;
typedef pair<int,int> PII;
typedef pair<double,double> PDD;
const int INF=0x3f3f3f3f,mod=1e9+7;
const ll INFF=1e18;
const double eps=1e-9;
mt19937 mrand(random_device{}());
template<class A, class B> ostream& operator <<(ostream& out, const pair<A, B> &p) {
return out << "(" << p.x << " " << p.y << ")";
}
template<class A> ostream& operator <<(ostream& out, const vector<A> &v) {
rep(i, 0, sz(v)) {
if(i) out << " ";
out << v[i];
}
return out;
}
int rnd(int x){return mrand()%x;}
ll qmi(ll a,ll b){ll res=1;a%=mod;while(b){if(b&1)res=res*a%mod;a=a*a%mod;b>>=1;}return res;}
ll qmul(ll a,ll b){ll res=0;a%=mod;while(b){if(b&1) res=(res+a)%mod;a=(a+a)%mod;b>>=1;} return res;}
ll gcd(ll a,ll b){return b?gcd(b,a%b):a;}
/*ll read()
{
ll x=0,f=1;char c=getchar();
while(c<'0'||c>'9'){if(c=='-')f=-1;c=getchar();}
while(c>='0'&&c<='9')x=x*10+(c-'0'),c=getchar();
return f*x;
}*/
//#include <iostream>
//#include <cstdio>
//#include <windows.h>
//#include <cstdlib>
//#include <ctime>
//using namespace std;
//int main()
//{
// int ok = 0;
// int n = 50;
// for (int i = 1; i <= n; ++i)
// {
// system("make.exe > make.txt");
// system("std.exe < make.txt > std.txt");
// double begin = clock();
// system("baoli.exe < make.txt > baoli.txt");
// double end = clock();
//
// double t = (end - begin);
// if (system("fc std.txt baoli.txt"))
// {
// printf("测试点#%d Wrong Answer\n", i);
// }
// else if (t > 1000) //1秒
// {
// printf("测试点#%d Time Limited Exceeded 用时 %.0lfms\n", i, t);
// }
// else
// {
// printf("测试点#%d Accepted 用时%.0lfms\n", i, t);
// ok++; //AC数量+1
// }
// }
// printf("\n");
// double res = 100.0 * ok / n;
// printf("共 %d 组测试数据，AC数据 %d 组。 得分%.1lf。", n, ok, res);
//
// Sleep(1000); //休眠1秒，为了节约对拍次数。
//}
inline int read()
{
int x=0;
char ch;
bool fx=false;
do ch=getchar();while(~ch&&ch!='-'&&(ch<48||ch>57));
if(ch=='-')fx=true,ch=getchar();
for(;ch>47&&ch<58;ch=getchar())
x=(x<<1)+(x<<3)+(ch^48);
return fx?-x:x;
}
const int N=520;
int t,n;
PII st,ed;
PII q[N*N];
int dist[N][N];
int d[8][2]={{-2,1},{-1,2},{-2,-1},{-1,-2},{1,2},{2,1},{1,-2},{2,-1}};
int bfs(int sx,int sy)
{
memset(dist,-1,sizeof(dist));
int hh=0,tt=0;
q[0]={sx,sy};
dist[sx][sy]=0;
while(hh<=tt)
{
PII t=q[hh++];
rep(i,0,8)
{
int a=t.x+d[i][0],b=t.y+d[i][1];
if(a<0||a>=n||b<0||b>=n) continue;
if(dist[a][b]!=-1) continue;
dist[a][b]=dist[t.x][t.y]+1,q[++tt]={a,b};
if(a==ed.x&&b==ed.y) return dist[a][b];
}
}
}
int main()
{
#ifdef my_test
freopen(".in","r",stdin);
freopen(".out","w",stdout);
#endif
#ifdef my_dp
while(1)
{
system("data.exe > in.txt");
system("brute.exe < in.txt > brute.txt");
system("std.exe < in.txt > std.txt");
if(system("fc std.txt brute.txt"))
break;
}
#endif
#ifdef my_dp2
while (1) //一直循环，直到找到不一样的数据
{
system("data.exe");
system("baoli.exe");
system("std.exe");
if (system("fc std.txt baoli.txt")) //当 fc 返回1时，说明这时数据不一样
break; //不一样就跳出循环
}
#endif
clock_t start,end;
start=clock();
t=read();
while(t--)
{
n=read();st.x=read(),st.y=read(),ed.x=read(),ed.y=read();
if(st.x==ed.x&&st.y==ed.y) puts("0");
else printf("%d\n",bfs(st.x,st.y));
}
end=clock();
// printf("%lfms\n",(double)(end-start)/CLOCKS_PER_SEC*1000);
return 0;
}
9
http://ybt.ssoier.cn:8088/problem_show.php?pid=1330
bfs求最短路
点击查看代码
#include<bits/stdc++.h>
#define rep(i,l,r) for(int i=int(l);i<int(r);i++)
#define per(i,r,l) for(int i=int(r-1);i>=int(l);i--)
#define repg(i,l,r) for(i=int(l);i<int(r);i++)
#define perg(i,r,l) for(int i=int(r-1);i>=int(l);i--)
#define rept(i,t) for(int i=int(h[t]);~i;i=ne[i])
#define reph(i,t,h) for(int i=int(h[t]);~i;i=ne[i])
#define x first
#define y second
#define pb push_back
#define pf push_front
#define ppb pop_back
#define ppf pop_front
#define all(x) (x).begin(),(x).end()
using namespace std;
typedef long long ll;
typedef unsigned long long lll;
typedef pair<int,int> PII;
typedef pair<double,double> PDD;
const int INF=0x3f3f3f3f,mod=1e9+7;
const ll INFF=1e18;
const double eps=1e-9;
mt19937 mrand(random_device{}());
template<class A, class B> ostream& operator <<(ostream& out, const pair<A, B> &p) {
return out << "(" << p.x << " " << p.y << ")";
}
template<class A> ostream& operator <<(ostream& out, const vector<A> &v) {
rep(i, 0, sz(v)) {
if(i) out << " ";
out << v[i];
}
return out;
}
int rnd(int x){return mrand()%x;}
ll qmi(ll a,ll b){ll res=1;a%=mod;while(b){if(b&1)res=res*a%mod;a=a*a%mod;b>>=1;}return res;}
ll qmul(ll a,ll b){ll res=0;a%=mod;while(b){if(b&1) res=(res+a)%mod;a=(a+a)%mod;b>>=1;} return res;}
ll gcd(ll a,ll b){return b?gcd(b,a%b):a;}
/*ll read()
{
ll x=0,f=1;char c=getchar();
while(c<'0'||c>'9'){if(c=='-')f=-1;c=getchar();}
while(c>='0'&&c<='9')x=x*10+(c-'0'),c=getchar();
return f*x;
}*/
//#include <iostream>
//#include <cstdio>
//#include <windows.h>
//#include <cstdlib>
//#include <ctime>
//using namespace std;
//int main()
//{
// int ok = 0;
// int n = 50;
// for (int i = 1; i <= n; ++i)
// {
// system("make.exe > make.txt");
// system("std.exe < make.txt > std.txt");
// double begin = clock();
// system("baoli.exe < make.txt > baoli.txt");
// double end = clock();
//
// double t = (end - begin);
// if (system("fc std.txt baoli.txt"))
// {
// printf("测试点#%d Wrong Answer\n", i);
// }
// else if (t > 1000) //1秒
// {
// printf("测试点#%d Time Limited Exceeded 用时 %.0lfms\n", i, t);
// }
// else
// {
// printf("测试点#%d Accepted 用时%.0lfms\n", i, t);
// ok++; //AC数量+1
// }
// }
// printf("\n");
// double res = 100.0 * ok / n;
// printf("共 %d 组测试数据，AC数据 %d 组。 得分%.1lf。", n, ok, res);
//
// Sleep(1000); //休眠1秒，为了节约对拍次数。
//}
inline int read()
{
int x=0;
char ch;
bool fx=false;
do ch=getchar();while(~ch&&ch!='-'&&(ch<48||ch>57));
if(ch=='-')fx=true,ch=getchar();
for(;ch>47&&ch<58;ch=getchar())
x=(x<<1)+(x<<3)+(ch^48);
return fx?-x:x;
}
const int N=520;
int t,n;
PII st,ed;
PII q[N*N];
int dist[N][N];
int d[12][2]={{-2,1},{-1,2},{-2,-1},{-1,-2},{1,2},{2,1},{1,-2},{2,-1},{2,2},{-2,-2},{2,-2},{-2,2}};
int bfs(int sx,int sy)
{
memset(dist,-1,sizeof(dist));
int hh=0,tt=0;
q[0]={sx,sy};
dist[sx][sy]=0;
while(hh<=tt)
{
PII t=q[hh++];
rep(i,0,12)
{
int a=t.x+d[i][0],b=t.y+d[i][1];
if(a<0||a>=100||b<0||b>=100) continue;
if(dist[a][b]!=-1) continue;
dist[a][b]=dist[t.x][t.y]+1,q[++tt]={a,b};
if(a==0&&b==0) return dist[a][b];
}
}
}
int main()
{
#ifdef my_test
freopen(".in","r",stdin);
freopen(".out","w",stdout);
#endif
#ifdef my_dp
while(1)
{
system("data.exe > in.txt");
system("brute.exe < in.txt > brute.txt");
system("std.exe < in.txt > std.txt");
if(system("fc std.txt brute.txt"))
break;
}
#endif
#ifdef my_dp2
while (1) //一直循环，直到找到不一样的数据
{
system("data.exe");
system("baoli.exe");
system("std.exe");
if (system("fc std.txt baoli.txt")) //当 fc 返回1时，说明这时数据不一样
break; //不一样就跳出循环
}
#endif
clock_t start,end;
start=clock();
t=1;
while(t--)
{
st.x=read(),st.y=read(),ed.x=read(),ed.y=read();
printf("%d\n",bfs(st.x-1,st.y-1));
printf("%d\n",bfs(ed.x-1,ed.y-1));
}
end=clock();
// printf("%lfms\n",(double)(end-start)/CLOCKS_PER_SEC*1000);
return 0;
}
http://ybt.ssoier.cn:8088/problem_show.php?pid=1253
选择问题，有一个trick就是在两倍<=k+2的时候选择可以选择乘二，这样是更优的，否则先减再2
点击查看代码
#include<bits/stdc++.h>
#define rep(i,l,r) for(int i=int(l);i<int(r);i++)
#define per(i,r,l) for(int i=int(r-1);i>=int(l);i--)
#define repg(i,l,r) for(i=int(l);i<int(r);i++)
#define perg(i,r,l) for(int i=int(r-1);i>=int(l);i--)
#define rept(i,t) for(int i=int(h[t]);~i;i=ne[i])
#define reph(i,t,h) for(int i=int(h[t]);~i;i=ne[i])
#define x first
#define y second
#define pb push_back
#define pf push_front
#define ppb pop_back
#define ppf pop_front
#define all(x) (x).begin(),(x).end()
using namespace std;
typedef long long ll;
typedef unsigned long long lll;
typedef pair<int,int> PII;
typedef pair<double,double> PDD;
const int INF=0x3f3f3f3f,mod=1e9+7;
const ll INFF=1e18;
const double eps=1e-9;
mt19937 mrand(random_device{}());
template<class A, class B> ostream& operator <<(ostream& out, const pair<A, B> &p) {
return out << "(" << p.x << " " << p.y << ")";
}
template<class A> ostream& operator <<(ostream& out, const vector<A> &v) {
rep(i, 0, sz(v)) {
if(i) out << " ";
out << v[i];
}
return out;
}
int rnd(int x){return mrand()%x;}
ll qmi(ll a,ll b){ll res=1;a%=mod;while(b){if(b&1)res=res*a%mod;a=a*a%mod;b>>=1;}return res;}
ll qmul(ll a,ll b){ll res=0;a%=mod;while(b){if(b&1) res=(res+a)%mod;a=(a+a)%mod;b>>=1;} return res;}
ll gcd(ll a,ll b){return b?gcd(b,a%b):a;}
/*ll read()
{
ll x=0,f=1;char c=getchar();
while(c<'0'||c>'9'){if(c=='-')f=-1;c=getchar();}
while(c>='0'&&c<='9')x=x*10+(c-'0'),c=getchar();
return f*x;
}*/
//#include <iostream>
//#include <cstdio>
//#include <windows.h>
//#include <cstdlib>
//#include <ctime>
//using namespace std;
//int main()
//{
// int ok = 0;
// int n = 50;
// for (int i = 1; i <= n; ++i)
// {
// system("make.exe > make.txt");
// system("std.exe < make.txt > std.txt");
// double begin = clock();
// system("baoli.exe < make.txt > baoli.txt");
// double end = clock();
//
// double t = (end - begin);
// if (system("fc std.txt baoli.txt"))
// {
// printf("测试点#%d Wrong Answer\n", i);
// }
// else if (t > 1000) //1秒
// {
// printf("测试点#%d Time Limited Exceeded 用时 %.0lfms\n", i, t);
// }
// else
// {
// printf("测试点#%d Accepted 用时%.0lfms\n", i, t);
// ok++; //AC数量+1
// }
// }
// printf("\n");
// double res = 100.0 * ok / n;
// printf("共 %d 组测试数据，AC数据 %d 组。 得分%.1lf。", n, ok, res);
//
// Sleep(1000); //休眠1秒，为了节约对拍次数。
//}
inline int read()
{
int x=0;
char ch;
bool fx=false;
do ch=getchar();while(~ch&&ch!='-'&&(ch<48||ch>57));
if(ch=='-')fx=true,ch=getchar();
for(;ch>47&&ch<58;ch=getchar())
x=(x<<1)+(x<<3)+(ch^48);
return fx?-x:x;
}
const int N=2e5+52;
int n,k;
int q[N];
int dist[N];
int bfs()
{
memset(dist,-1,sizeof(dist));
dist[n]=0;q[0]=n;
int hh=0,tt=0;
while(hh<=tt)
{
int t=q[hh++];
if(t==k) return dist[k];
if(t+1<=k&&dist[t+1]==-1) dist[t+1]=dist[t]+1,q[++tt]=t+1;
if(t-1>=0&&dist[t-1]==-1) dist[t-1]=dist[t]+1,q[++tt]=t-1;
if(t*2<=(k+3)&&dist[t*2]==-1) dist[t*2]=dist[t]+1,q[++tt]=t*2;
}
return -1;
}
int main()
{
#ifdef my_test
freopen(".in","r",stdin);
freopen(".out","w",stdout);
#endif
#ifdef my_dp
while(1)
{
system("data.exe > in.txt");
system("brute.exe < in.txt > brute.txt");
system("std.exe < in.txt > std.txt");
if(system("fc std.txt brute.txt"))
break;
}
#endif
#ifdef my_dp2
while (1) //一直循环，直到找到不一样的数据
{
system("data.exe");
system("baoli.exe");
system("std.exe");
if (system("fc std.txt baoli.txt")) //当 fc 返回1时，说明这时数据不一样
break; //不一样就跳出循环
}
#endif
clock_t start,end;
start=clock();
n=read(),k=read();
printf("%d\n",bfs());
end=clock();
// printf("%lfms\n",(double)(end-start)/CLOCKS_PER_SEC*1000);
return 0;
}
http://ybt.ssoier.cn:8088/problem_show.php?pid=1255
还是bfs最短路问题，只不过需要打印路径，打印路径记录前驱，要么while，要么递归来写，很方便
点击查看代码
#include<bits/stdc++.h>
#define rep(i,l,r) for(int i=int(l);i<int(r);i++)
#define per(i,r,l) for(int i=int(r-1);i>=int(l);i--)
#define repg(i,l,r) for(i=int(l);i<int(r);i++)
#define perg(i,r,l) for(int i=int(r-1);i>=int(l);i--)
#define rept(i,t) for(int i=int(h[t]);~i;i=ne[i])
#define reph(i,t,h) for(int i=int(h[t]);~i;i=ne[i])
#define x first
#define y second
#define pb push_back
#define pf push_front
#define ppb pop_back
#define ppf pop_front
#define all(x) (x).begin(),(x).end()
using namespace std;
typedef long long ll;
typedef unsigned long long lll;
typedef pair<int,int> PII;
typedef pair<double,double> PDD;
const int INF=0x3f3f3f3f,mod=1e9+7;
const ll INFF=1e18;
const double eps=1e-9;
mt19937 mrand(random_device{}());
template<class A, class B> ostream& operator <<(ostream& out, const pair<A, B> &p) {
return out << "(" << p.x << " " << p.y << ")";
}
template<class A> ostream& operator <<(ostream& out, const vector<A> &v) {
rep(i, 0, sz(v)) {
if(i) out << " ";
out << v[i];
}
return out;
}
int rnd(int x){return mrand()%x;}
ll qmi(ll a,ll b){ll res=1;a%=mod;while(b){if(b&1)res=res*a%mod;a=a*a%mod;b>>=1;}return res;}
ll qmul(ll a,ll b){ll res=0;a%=mod;while(b){if(b&1) res=(res+a)%mod;a=(a+a)%mod;b>>=1;} return res;}
ll gcd(ll a,ll b){return b?gcd(b,a%b):a;}
/*ll read()
{
ll x=0,f=1;char c=getchar();
while(c<'0'||c>'9'){if(c=='-')f=-1;c=getchar();}
while(c>='0'&&c<='9')x=x*10+(c-'0'),c=getchar();
return f*x;
}*/
//#include <iostream>
//#include <cstdio>
//#include <windows.h>
//#include <cstdlib>
//#include <ctime>
//using namespace std;
//int main()
//{
// int ok = 0;
// int n = 50;
// for (int i = 1; i <= n; ++i)
// {
// system("make.exe > make.txt");
// system("std.exe < make.txt > std.txt");
// double begin = clock();
// system("baoli.exe < make.txt > baoli.txt");
// double end = clock();
//
// double t = (end - begin);
// if (system("fc std.txt baoli.txt"))
// {
// printf("测试点#%d Wrong Answer\n", i);
// }
// else if (t > 1000) //1秒
// {
// printf("测试点#%d Time Limited Exceeded 用时 %.0lfms\n", i, t);
// }
// else
// {
// printf("测试点#%d Accepted 用时%.0lfms\n", i, t);
// ok++; //AC数量+1
// }
// }
// printf("\n");
// double res = 100.0 * ok / n;
// printf("共 %d 组测试数据，AC数据 %d 组。 得分%.1lf。", n, ok, res);
//
// Sleep(1000); //休眠1秒，为了节约对拍次数。
//}
inline int read()
{
int x=0;
char ch;
bool fx=false;
do ch=getchar();while(~ch&&ch!='-'&&(ch<48||ch>57));
if(ch=='-')fx=true,ch=getchar();
for(;ch>47&&ch<58;ch=getchar())
x=(x<<1)+(x<<3)+(ch^48);
return fx?-x:x;
}
const int N=52;
PII q[N*N],pre[N][N];
int d[4][2]={{1,0},{0,1},{-1,0},{0,-1}};
int dist[N][N];
int g[N][N];
void print(int sx,int sy)
{
if(sx==-1&&sy==-1) return;
print(pre[sx][sy].x,pre[sx][sy].y);
printf("(%d, %d)\n",sx,sy);
}
void bfs(int sx,int sy)
{
memset(dist,-1,sizeof(dist));
int hh=0,tt=0;
q[0]={sx,sy};
pre[sx][sy]={-1,-1};
dist[sx][sy]=0;
while(hh<=tt)
{
PII t=q[hh++];
rep(i,0,4)
{
int a=t.x+d[i][0],b=t.y+d[i][1];
if(a<0||a>=5||b<0||b>=5) continue;
if(dist[a][b]!=-1||g[a][b]==1) continue;
dist[a][b]=dist[t.x][t.y]+1,q[++tt]={a,b},pre[a][b]={t.x,t.y};
}
}
print(4,4);
}
int main()
{
#ifdef my_test
freopen(".in","r",stdin);
freopen(".out","w",stdout);
#endif
#ifdef my_dp
while(1)
{
system("data.exe > in.txt");
system("brute.exe < in.txt > brute.txt");
system("std.exe < in.txt > std.txt");
if(system("fc std.txt brute.txt"))
break;
}
#endif
#ifdef my_dp2
while (1) //一直循环，直到找到不一样的数据
{
system("data.exe");
system("baoli.exe");
system("std.exe");
if (system("fc std.txt baoli.txt")) //当 fc 返回1时，说明这时数据不一样
break; //不一样就跳出循环
}
#endif
clock_t start,end;
start=clock();
rep(i,0,5) rep(j,0,5) g[i][j]=read();
bfs(0,0);
end=clock();
// printf("%lfms\n",(double)(end-start)/CLOCKS_PER_SEC*1000);
return 0;
}
12
水水的三维bfs
http://ybt.ssoier.cn:8088/problem_show.php?pid=1248
点击查看代码
#include<bits/stdc++.h>
#define rep(i,l,r) for(int i=int(l);i<int(r);i++)
#define per(i,r,l) for(int i=int(r-1);i>=int(l);i--)
#define repg(i,l,r) for(i=int(l);i<int(r);i++)
#define perg(i,r,l) for(int i=int(r-1);i>=int(l);i--)
#define rept(i,t) for(int i=int(h[t]);~i;i=ne[i])
#define reph(i,t,h) for(int i=int(h[t]);~i;i=ne[i])
#define x first
#define y second
#define pb push_back
#define pf push_front
#define ppb pop_back
#define ppf pop_front
#define all(x) (x).begin(),(x).end()
using namespace std;
typedef long long ll;
typedef unsigned long long lll;
typedef pair<int,int> PII;
typedef pair<double,double> PDD;
const int INF=0x3f3f3f3f,mod=1e9+7;
const ll INFF=1e18;
const double eps=1e-9;
mt19937 mrand(random_device{}());
template<class A, class B> ostream& operator <<(ostream& out, const pair<A, B> &p) {
return out << "(" << p.x << " " << p.y << ")";
}
template<class A> ostream& operator <<(ostream& out, const vector<A> &v) {
rep(i, 0, sz(v)) {
if(i) out << " ";
out << v[i];
}
return out;
}
int rnd(int x){return mrand()%x;}
ll qmi(ll a,ll b){ll res=1;a%=mod;while(b){if(b&1)res=res*a%mod;a=a*a%mod;b>>=1;}return res;}
ll qmul(ll a,ll b){ll res=0;a%=mod;while(b){if(b&1) res=(res+a)%mod;a=(a+a)%mod;b>>=1;} return res;}
ll gcd(ll a,ll b){return b?gcd(b,a%b):a;}
/*ll read()
{
ll x=0,f=1;char c=getchar();
while(c<'0'||c>'9'){if(c=='-')f=-1;c=getchar();}
while(c>='0'&&c<='9')x=x*10+(c-'0'),c=getchar();
return f*x;
}*/
//#include <iostream>
//#include <cstdio>
//#include <windows.h>
//#include <cstdlib>
//#include <ctime>
//using namespace std;
//int main()
//{
// int ok = 0;
// int n = 50;
// for (int i = 1; i <= n; ++i)
// {
// system("make.exe > make.txt");
// system("std.exe < make.txt > std.txt");
// double begin = clock();
// system("baoli.exe < make.txt > baoli.txt");
// double end = clock();
//
// double t = (end - begin);
// if (system("fc std.txt baoli.txt"))
// {
// printf("测试点#%d Wrong Answer\n", i);
// }
// else if (t > 1000) //1秒
// {
// printf("测试点#%d Time Limited Exceeded 用时 %.0lfms\n", i, t);
// }
// else
// {
// printf("测试点#%d Accepted 用时%.0lfms\n", i, t);
// ok++; //AC数量+1
// }
// }
// printf("\n");
// double res = 100.0 * ok / n;
// printf("共 %d 组测试数据，AC数据 %d 组。 得分%.1lf。", n, ok, res);
//
// Sleep(1000); //休眠1秒，为了节约对拍次数。
//}
inline int read()
{
int x=0;
char ch;
bool fx=false;
do ch=getchar();while(~ch&&ch!='-'&&(ch<48||ch>57));
if(ch=='-')fx=true,ch=getchar();
for(;ch>47&&ch<58;ch=getchar())
x=(x<<1)+(x<<3)+(ch^48);
return fx?-x:x;
}
const int N=52;
char g[N][N][N];
int d[6][3]={{1,0,0},{0,1,0},{-1,0,0},{0,-1,0},{0,0,1},{0,0,-1}};
int dist[N][N][N];
int h,n,m;
int sz,sx,sy;
struct point
{
int z,x,y;
}q[N*N*N];
int bfs(int sz,int sx,int sy)
{
memset(dist,-1,sizeof(dist));
int hh=0,tt=0;
q[0]={sz,sx,sy};
dist[sz][sx][sy]=0;
while(hh<=tt)
{
point t=q[hh++];
rep(i,0,6)
{
int c=t.z+d[i][0],a=t.x+d[i][1],b=t.y+d[i][2];
if(c<0||c>=h||a<0||a>=n||b<0||b>=m) continue;
if(g[c][a][b]=='#'||dist[c][a][b]!=-1) continue;
dist[c][a][b]=dist[t.z][t.x][t.y]+1;q[++tt]={c,a,b};
if(g[c][a][b]=='E') return dist[c][a][b];
}
}
return -1;
}
int main()
{
#ifdef my_test
freopen(".in","r",stdin);
freopen(".out","w",stdout);
#endif
#ifdef my_dp
while(1)
{
system("data.exe > in.txt");
system("brute.exe < in.txt > brute.txt");
system("std.exe < in.txt > std.txt");
if(system("fc std.txt brute.txt"))
break;
}
#endif
#ifdef my_dp2
while (1) //一直循环，直到找到不一样的数据
{
system("data.exe");
system("baoli.exe");
system("std.exe");
if (system("fc std.txt baoli.txt")) //当 fc 返回1时，说明这时数据不一样
break; //不一样就跳出循环
}
#endif
clock_t start,end;
start=clock();
while(h=read(),n=read(),m=read(),h,n,m)
{
rep(i,0,h) rep(j,0,n) scanf("%s",g[i][j]);
rep(i,0,h) rep(j,0,n) rep(k,0,m) if(g[i][j][k]=='S') sz=i,sx=j,sy=k;
int ans=bfs(sz,sx,sy);
if(ans==-1)puts("Trapped!");
else printf("Escaped in %d minute(s).\n",ans);
}
end=clock();
// printf("%lfms\n",(double)(end-start)/CLOCKS_PER_SEC*1000);
return 0;
}
标签：std,int,ll,system,一本,通刷题,txt,define 来源： https://www.cnblogs.com/Astronaut0142/p/15783614.html
本站声明： 1. iCode9 技术分享网（下文简称本站）提供的所有内容，仅供技术学习、探讨和分享； 2. 关于本站的所有留言、评论、转载及引用，纯属内容发起人的个人观点，与本站观点和立场无关； 3. 关于本站的所有言论和文字，纯属内容发起人的个人观点，与本站观点和立场无关； 4. 本站文章均是网友提供，不完全保证技术分享内容的完整性、准确性、时效性、风险性和版权归属；如您发现该文章侵犯了您的权益，可联系我们第一时间进行删除； 5. 本站为非盈利性的个人网站，所有内容不会用来进行牟利，也不会利用任何形式的广告来间接获益，纯粹是为了广大技术爱好者提供技术内容和技术思想的分享性交流网站。