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  • openstack: No valid host was found. There are not enough hosts available2021-06-03 22:57:34

    这个问题,可以先重启nova和neutron中的服务,再重启 如果依旧出现这样的问题,可以中下面进行排查 这个问题产生的很大原因有: 1)计算节点的内存不足、CPU资源不够、硬盘空间资源不足造成的;将云主机类型规格调小点,发现就能创建成功。      计算节点将新建的虚拟机存放在/var/lib/nova/

  • Codeforces Round #721 (Div. 2)A. And Then There Were K(位运算,二进制) B1. Palindrome Game (easy version2021-05-22 21:03:28

    半个月没看cf 手生了很多(手动大哭)     Problem - A - Codeforces 题意 给定数字n, 求出最大数字k, 使得  n & (n−1) & (n−2) & (n−3) & ... (k) = 0 题解 &:有0则0 假如n转为二进制共有x位 , 要使&后=0, k的最高位需=0 我们使最高位=0,后面都为1; 那么此数+1=什么 =100

  • 英语模板作文,词组,句子,句型,开头2021-05-22 17:29:51

    模板英语/词组/句子 文章目录 万能背景简洁版万能背景替换版 万能背景替换版part3经济类人口类社会类技术类教育类环境类家庭类 范文短语传统文化类旅游城市类科学教育类政治经济类 大学英语读写词汇篇替换词连接词万能句型简洁版一、开头二、结尾三、表比较四、表原因五

  • 【leetcode】1608. Special Array With X Elements Greater Than or Equal X2021-05-21 17:35:26

    题目如下: You are given an array nums of non-negative integers. nums is considered special if there exists a number x such that there are exactly x numbers in nums that are greater than or equal to x. Notice that x does not have to be an ele

  • 2021-2022学年学英语报八年级第20期答案及试题2021-05-19 20:04:02

    进入查看:2021-2022学年学英语报八年级第20期答案及试题   Death Valley is a beautiful but extremely(极端 ) dangerous land. There high mountains reach more than 3000 meters into the sky. But there is also a low place called Badwater. It is the lowest area of land

  • 剑10 - 剑15 精听记录2021-05-15 16:35:18

    10-T1S1: Good morning, well tours, my name is Jimmy, how can I help you ? -Good morning, world tours, my name is Jamie, how can I help you ? Good morning, I would see the information on self-drive tours in USA,could you send me a brushure? -Good morning,

  • 【Rust日报】2020-11-09 构建可测试性的 Rust 工程2021-05-08 18:01:41

    构建可测试性的 Rust 工程最近 reddit 上有不少人对 Rust 的工程如何进行组织, 以及如何才能进行更加完善的测试进行了一些讨论.下面的文章给出了一个 web 服务的例子, 演示了如何来组织 Rust 中的模块, 以及如何让代码更加具有测试性.原文链接: https://medium.com/bette

  • Is There A Second Way Left? UVA - 104622021-05-05 15:35:11

    原题链接 考察:次小生成树 思路:         yysy,切模板题很爽,但是莫得进步555         时间复杂度:O(T*(mlog2m+n2+m)) 1 #include <iostream> 2 #include <cstring> 3 #include <algorithm> 4 using namespace std; 5 const int N = 110,M = 210,INF = 0x3f3f3f3f;

  • pycharm 报错 ModuleNotFoundError: No module named '_cffi_backend'2021-05-01 22:03:08

    Here's the output of pip freeze, for reference:[root@machine ~]# pip freeze argparse==1.2.1 autobahn==0.8.10 cffi==1.5.2 characteristic==14.3.0 pika==0.9.13 pyasn1==0.1.7 pyasn1-modules==0.0.8 pycparser==2.14 pycrypto==2.6.1 pyOpenSSL==0.12 pysnmp==4

  • 英语-基础语法-主宾表2021-04-30 19:34:58

    主语的成分 名词 代词 非谓语动词 从句 帅气和强壮是他的特点 Handsome and strong are his nature. 上面这个句子是错误的,因为主语不能是形容词 改为: Handsomeness and strength are his nature. 或者是 Being handsome and strong are his nature. 如果没有主语: 1)加it作为主

  • There is a chart instance already initialized on the dom2021-04-23 13:58:36

    参考API文档 http://echarts.baidu.com/api.html#echarts.dispose 添加链接描述 1.取得DOM let main = document.getElementById("main"); 2.判段是否已有实例 let existInstance = echarts.getInstanceByDom(main); if (existInstance) { if (true) { echarts.

  • Python列表的常用操作2021-04-16 15:05:13

    列表的增删改查,排序'''#代码开始 list_1=['gong','juanxu','jing'] print(list_1[2]) list_1[2]="xia" #添加一个元素 print(list_1) print("Wellcome to there ",list_1[0]) print("Wellcome to there ",list_1[1]

  • PAT (Advanced Level) Practice 1035 Password (20 分) 凌宸16422021-04-03 15:05:19

    PAT (Advanced Level) Practice 1035 Password (20 分) 凌宸1642 题目描述: To prepare for PAT, the judge sometimes has to generate random passwords for the users. The problem is that there are always some confusing passwords since it is hard to distinguish 1 (one

  • 解决Error: Cannot find module ‘are-we-there-yet‘ npm无法使用2021-03-23 10:57:52

    今天登陆服务器提示这个 ,并且npm无法运行 module.js:557 throw err; ^ Error: Cannot find module 'are-we-there-yet' at Function.Module._resolveFilename (module.js:555:15) at Function.Module._load (module.js:482:25) at Module.require (modu

  • vim 基础知识2021-03-13 21:03:18

    leader https://vi.stackexchange.com/questions/836/what-is-leader Vim is full of various commands, which are assigned to almost all keys on the keyboard. But this causes a problem: Which commands can we use for our own commands, without interfering with ex

  • Python周刊487期2021-02-28 22:32:55

    Python周刊 欢迎阅读《 Python周刊》第487期。 写在前面:翻译不易,欢迎阅读;水平有限,万望海涵。部分链接可能需要特殊的上网方式(

  • MP:There is no getter for property named ‘null‘ in ‘class XXX‘异常2021-02-23 17:00:16

    在使用主键进行更新或者删除的时候,报下面错误 There is no getter for property named ‘null’ in 'class 。。。 我的代码如下 @Builder @Data public class Course implements Serializable { private static final long serialVersionUID = -16929324809307129L;

  • Python周刊486期2021-02-22 22:01:17

    Python周刊 欢迎阅读《 Python周刊》第486期。 写在前面:翻译不易,欢迎阅读;水平有限,万望海涵。部分链接可能需要特殊的上网方式(

  • [LeetCode 1504] Count Submatrices With All Ones2021-02-16 06:32:50

    Given a rows * columns matrix mat of ones and zeros, return how many submatrices have all ones.   Example 1: Input: mat = [[1,0,1],   [1,1,0],   [1,1,0]] Output: 13 Explanation: There are 6 rectangles of side 1x1. There are 2

  • 1035 Password (20 分)2021-02-14 10:02:41

    水题~。 map<char,char> mp; int n; void init() { mp['1']='@'; mp['0']='%'; mp['l']='L'; mp['O']='o'; } int main() { init(); cin>>n; vec

  • 圈叉棋 Tic Tac Toe实现与AI分析2021-01-26 18:33:36

    简介 井字棋 圈叉棋 Tic Tac Toe 原理 用数组代表棋子的位置,可以1x9也可以3x3 判断胜利 井字棋有八种胜利的方式,三横三竖两对角线,逐个遍历即可判定是否胜利,参考一就是遍历六次加上对角线,个人觉得参考三的七个or更优美简洁一点吧。 AI算法 算法思路在书上写的很明白 The AI

  • 2020-2021学年广州市花都区九年级第一学期期末考试英语试题2021-01-25 17:30:52

    In a room, there were four candles burning. It was 1 quiet that you could hear them Monty Roberts was the son of a horse trainer who would go from farm to farm and ranch to It was my first year of teaching in a special needs classroom and I wasn’t sure

  • mybatis there is no getter named for"Integer"2021-01-11 07:06:46

    JAVA就业套餐课:https://edu.csdn.net/combo/detail/1230一:发现问题sql动态语句中如果 parameterType="int"    <select id="sel_campusinfo" parameterType="int" resultType="Campusinfo">             select cmpid,cmpname from campusinfo

  • 个人总结---Where there's a will there's a way!2021-01-07 02:03:17

    做了哪些作业: * 第一次个人作业 * 第一次个人编程作业:我的分数我做主 * 第二次个人编程作业:代码互改 * 第一次结对作业 * 第二次结对作业:班级成绩表 * 第三次结对作业:需求建模练习 * 码上收集007 ——团队展示 * 团队作业第二次 —— 项目介绍 * 团队作业第三次 —— UML设计 *

  • Linux,yum错误,There are no enabled repos.(学习)2020-12-19 17:02:05

    1.yum yum(全称为 Yellow dog Updater, Modified)是一个在Fedora和RedHat以及SUSE中的Shell前端软件包管理器。基於RPM包(RPM 是 Red Hat Package Manager 的缩写,本意是Red Hat 软件包管理,顾名思义是Red Hat 贡献出来的软件包管理)管理,能够从指定的服务器自动下载RPM包并且安装,可以

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