ICode9

精准搜索请尝试: 精确搜索
  • HDLBits答案——Circuits2022-08-22 16:01:23

    1 Combinational Logic 1.1 Basic Gates 1.1.1 Exams/m2014 q4h module top_module ( input in, output out); assign out = in; endmodule 1.1.2 Exams/m2014 q4i module top_module ( output out); assign out = 1'b0; endmodule 1.1.3 Exams/m2014

  • HDLBits答案——Getting started2022-08-16 19:30:27

    Getting started 1 Step one module top_module( output one ); // Insert your code here assign one = 1'b1; endmodule 2 Zero module top_module( output zero );// Module body starts after semicolon assign zero = 0; endmodule

  • Verilog 练习 反相器2021-11-01 23:02:35

     代码如下 //2021-11-1 //反相器 `timescale 1ns/10ps module inv(A,Y); output Y; input A; assign Y=~A; endmodule //----testbench of inv------ module inv_tb; reg aa; wire yy; inv inv(.A(aa),.Y(yy)); initial begin aa=0; #10 aa=1; #10 aa=0; #10 aa=1;

  • HDLBits 系列(1)2021-09-08 00:02:55

    目录 本篇文章主要包含以下问题的解析,这部分是最基本的,不作解读。 1.Getting Started 1.1 Step one   赋值输出1 1.2 Zero  赋值输出0 2.Verilog Language  ——Problems that focus on introducing Verilog language syntax and features. 2.1 Basics     1.Create a

  • 2021-06-302021-06-30 13:02:30

    https://www.bilibili.com/video/BV14L411p7Zn/ 本实验为quartus ii 与modelism联合仿真的实验 代码为module upcount (Resetn, Clock, E, Q;input Resetn, Clock, E; output reg [3:0] Q; always @(negedge Resetn, posedge Clock)if(!Resetn) Q<= 0; else if (E) Q<=Q+ l;

  • 【HDLbits答案】Verilog Language-Combinational Logic(其一)2021-03-04 21:32:18

    因为目录Verilog Language-Combinational Logic下的练习题有点多,我还没做完,今天先发Basic Gates与Multiplexers下的。 Basic Gates in_out module top_module ( input in, output out); assign out = in ; endmodule Exams/m2014 q4i module top_module ( output o

  • Verilog基础入门——简单的语句块编写(二)2020-10-04 22:04:02

      【题干】     【代码】 module top_module( input a, input b, output out ); assign out = a&b; endmodule 【与或非门等】 module top_module( input a, input b, output [5:0]out ); assign out[0] = a&b;   //与 assign out[1] = a|

专注分享技术,共同学习,共同进步。侵权联系[81616952@qq.com]

Copyright (C)ICode9.com, All Rights Reserved.

ICode9版权所有