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  • 关于爬取babycenter.com A-Z为顺序的所有英文名及其详细属性2019-12-20 17:04:20

     这一次爬取的内容已经在标题里提到了,下面是详细要求及其图示: 1、首先以A-Z的顺序获取所有英文名,最后爬取该英文名的详细信息。 2、CSV的header以3中的单词为准,请别拼错。如果没有对应的数据,该列留空。  3、最终CSV中的字段名以此为准:EnName,CnName,Gender,Meaning,Description,Sour

  • LeetCode_482. License Key Formatting2019-12-13 11:58:12

      482. License Key Formatting Easy You are given a license key represented as a string S which consists only alphanumeric character and dashes. The string is separated into N+1 groups by N dashes. Given a number K, we would want to reformat the stri

  • 1031 Hello World for U (20分)2019-12-08 16:02:27

    Given any string of N (≥) characters, you are asked to form the characters into the shape of U. For example, helloworld can be printed as: h d e l l r lowo That is, the characters must be printed in the original order, starting top-down from the lef

  • How to use special characters in XML?2019-11-23 13:03:31

    https://dvteclipse.com/documentation/svlinter/How_to_use_special_characters_in_XML.3F.html   Because XML syntax uses some characters for tags and attributes it is not possible to directly use those characters inside XML tags or attribute values. To includ

  • LeetCode 205. Isomorphic Strings C++2019-09-23 11:50:24

    Given two strings s and t, determine if they are isomorphic. Two strings are isomorphic if the characters in s can be replaced to get t. All occurrences of a character must be replaced with another character while preserving the order of characters. No

  • Characters with Hash[签到题]2019-08-30 15:05:55

    目录 题目地址 题干 代码和解释 参考 题目地址 Characters with Hash(ACM-ICPC 2018 徐州赛区网络预赛) 题干 代码和解释 本题很好理解,通过一个seed,将输入的定长字符串的每个字符依次转化为一个两位数字(一位则在前添加0),将这些数字依次排列,去掉左侧开头的0,输出这串数字的位数

  • 泡泡一分钟:Teaching Robots to Draw2019-08-25 15:58:35

    Teaching Robots to Draw 教会机器人画画https://h2r.cs.brown.edu/wp-content/uploads/kotani19.pdf Atsunobu Kotani and Stefanie Tellex In this paper, we introduce an approach which enables manipulator robots to write handwritten characters or line drawings. Given

  • SEO笔记:构建URL的15个SEO最佳实践2019-08-08 18:07:08

    原文链接:http://www.cnblogs.com/daisy-popule/p/seo-best-practices-for-structuring-urls.html By: Rand Fishkin 原文链接:https://moz.com/blog/15-seo-best-practices-for-structuring-urls   #1: Whenever possible, use a single domain & subd

  • TCL Strings2019-08-01 11:52:23

    append    Append values to variable binary      Insert and extract fields from binary strings format      printf() -style string formatting regexp      Regular expression pattern matching regsub      Regular expression string substution scan   

  • 482. License Key Formatting2019-07-31 21:07:38

    You are given a license key represented as a string S which consists only alphanumeric character and dashes. The string is separated into N+1 groups by N dashes. Given a number K, we would want to reformat the strings such that each group contains exactly

  • Josephina and RPG ZOJ - 37352019-07-26 23:03:55

     Josephina and RPG ZOJ - 3735 A role-playing game (RPG and sometimes roleplaying game) is a game in which players assume the roles of characters in a fictional setting. Players take responsibility for acting out these roles within a narrative, either thro

  • Nodepad++ 没有TextFX Characters插件2019-07-15 12:52:23

    Nodepad++ 没有TextFX Characters插件 原因:从6.5以上的某个版本开始,就没有了默认的这个插件。 我试了最新的版本下载插件也不行,只好下载一个6.4.5的版本,再更新插件管理器。 下载了一个TextFX Characters插件动态库,复制到Plugin目录下,再到设置里导入,重启软件,就可以了。

  • UnicodeEncodeError: 'latin-1' codec can't encode characters in position 289-2019-07-07 13:37:29

    UnicodeEncodeError: ‘latin-1’ codec can’t encode characters in position 289- Python运行时报错的解决办法: 文件命名时不要带中文,用英文命名即可

  • LeetCode.1002-寻找共有字符(Find Common Characters)2019-07-06 11:51:48

    这是悦乐书的第375次更新,第402篇原创 01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第236题(顺位题号是1002)。给定仅由小写字母组成的字符串A,返回列表中所有字符串都有显示的字符的列表(包括重复字符)。例如,如果一个字符在所有字符串中出现3次但不是4次,则需要在最终答案中包

  • CodeForces 903E Swapping Characters2019-07-01 09:43:49

    Swapping Characters 题解: 先算出其他串和第一个串的字母个数是否相同。 再算出其他串和第一个串不同的字母位置个数。 然后枚举第一个串交换的位置。 计算交换之后的不同字母的位置个数。 如果个数为0,则至少有2个相同的字母。 如果个数为2,则说明交换那2个位置之后可以相同。   代

  • C#实现整型数据字任意编码任意进制的转换和逆转换2019-06-27 23:27:26

    实现如下: using System; using System.Collections.Generic; using System.Linq; using System.Text;  namespace ConsoleApplication1 {      public class Number     {         public string Characters         {            

  • 解决UnicodeEncodeError: 'ascii' codec can't encode characters in position2019-06-13 08:49:17

    为什么80%的码农都做不了架构师?>>>    最近用Python写了些爬虫,在爬取一个gb2312的页面时,抛出异常:UnicodeEncodeError: 'ascii' codec can't encode characters in position 21-23: ordinal not in range(128)解决方案如下:首先设置系统的默认编码为utf-8:impor

  • leetcode 395 Longest Substring with At Least K Repeating Characters2019-06-12 15:00:06

    lc395  Longest Substring with At Least K Repeating Characters 思路是按子串中不同字母的个数来计算,1~26 每次计算n个不同字母所能构成的最长子串 记录其中最长子串   单次循环中,用双指针end向后遍历s,begin用来计算子串长度 当见过的字母个数 == n且这些字母出现次数都大于等

  • 大数据Shell编程 之 常用正则表达式2019-06-07 22:40:01

      ^ 行首$ 行尾. 除了换行符以外的任意单个字符* 前导字符的零个或多个.* 所有字符[] 字符组内的任一字符[^] 对字符组内的每个字符取反(不匹配字符组内的每个字符)^[^] 非字符组内的字符开头的行[a-z] 小写字母[A-Z] 大写字母[a-Z] 小写和大写字母[0-9] 数字\< 单词头 单词一般

  • 字符串大小写字母互换2019-06-02 09:51:25

    1 #include <stdio.h> 2 3 int main() 4 { 5 char ch; 6 printf("input characters:"); 7 ch = getchar(); 8 while (ch!='\n') 9 {10 if (ch >= 'A' && ch <= 'Z')11 {

  • A. Love "A"2019-05-14 12:52:39

    题目链接 Alice has a string s. She really likes the letter “a”. She calls a string good if strictly more than half of the characters in that string are "a"s. For example “aaabb”, “axaa” are good strings, and “baca”, “awwwa”, “” (empty string)

  • 344. Reverse String2019-05-06 20:40:37

    Question: Write a function that reverses a string. The input string is given as an array of characters char[]. Do not allocate extra space for another array, you must do this by modifying the input array in-place with O(1) extra memory. You may assume all

  • Java中字符表示形式2019-05-06 13:54:41

    Which characters does JVM use? (   ) A.  ASCII characters                B.  Unicode characters C.  Cp1252                              D.  UTF-8 答案:B 在Java中字符只以一种形式存在——Unicode,即不选择任何特定的编码,直接使用它们在字

  • [POJ 2176] Folding2019-05-03 13:52:43

    问题描述 Bill is trying to compactly represent sequences of capital alphabetic characters from 'A' to 'Z' by folding repeating subsequences inside them. For example, one way to represent a sequence AAAAAAAAAABABABCCD is 10(A)2(BA)B2(C)D. H

  • Java高级特性 第14节 解析XML文档(2) - SAX 技术2019-04-27 18:52:22

    一、SAX解析XML文档   SAX的全称是Simple APIs for XML,也即XML简单应用程序接口。与DOM不同,SAX提供的访问模式是一种顺序模式,这是一种快速读写XML数据的方式。当使用SAX分析器对XML文档进行分析时,会触发一系列事件,并激活相应的事件处理函数,应用程序通过这些事件处理函数实现对XML

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