原题传送门 1. 问题描述 2. Solution 1、思路分析 定义数组保存结果，依次读入A, B行，指数为下标，系数为值累加到结果数组中 2、代码实现 // PAT Advance Level 1002 // Ye Qiu #include <iostream> #include <string> using namespace std; /* 定义数组保存结果，依次读入A, B行
PAT 甲级 1001 A+B Format PAT 甲级 1002 A+B for Polynomials PAT 甲级 1003 Emergency DFS PAT 甲级 1004 Counting Leaves PAT 甲级 1005 Spell It Right 模拟 字符串 PAT 甲级 1006 Sign In and Sign Out 字符串 PAT 甲级 1007 Maximum Subsequence Sum dp PAT 甲级 1008 Elev
1002 A+B for Polynomials part 1, 1.1 自己解法(未全对) 使用两个map去存储数据 #include <iostream> using namespace std; #include <map> #include <algorithm> #include <iomanip> class MyCompare { public: bool operator()(int v1, int v2) {
This time, you are supposed to find A*B where A and B are two polynomials. Input Specification: Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynomial: K N1 aN1 N2 aN2 … NK aNK, where K i
题目描述 题目理解 题目大意是给我们两个多项式序列，要求计算出两个多项式的和 示例给出的answer格式是： 项数X的次数值X的次数值X的次数值321.512.903.2 代码实现 用两个数组记录输入；遍历一遍相加；把非0项统计并用ans记录；从大到小遍历数组从而实现X的次数从高到低；用printf控制
【1002】 A+B for Polynomials (25 分) 1 //1002 A+B for Polynomials (25 分) 2 #include<iostream> 3 #include<iomanip> 4 using namespace std; 5 double a[1001] = { 0 }; 6 int main() { 7 int k,n,count=0; 8 double x; 9 int group
A1009 Product of Polynomials (多项式乘法) This time, you are supposed to find A×B where A and B are two polynomials. Input Specification: Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a pol
A1002 A+B for Polynomials Input SpecificationOutput SpecificationSample InputSample OutputCode This time, you are supposed to find A+B where A and B are two polynomials. Input Specification Each input file contains one test case. Each case occupies
This time, you are supposed to find A×B where A and B are two polynomials. Input Specification: Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynomial:K N1 aN1 N2 aN2 ... NK aNK where
目录 题目代码测试结果 题目 Sample Input: 2 1 2.4 0 3.2 2 2 1.5 1 0.5 Sample Output: 3 2 1.5 1 2.9 0 3.2 代码 #include <stdio.h> int main() { int i,j,m,x; float p[1001]={0},q; for(i=0;i<2;i++){ scanf("%d",&m); for(
目录 0、Gauss型积分通用形式 1、Gauss–Legendre quadrature勒让德 2、Gauss–Laguerre quadrature拉盖尔——积分区间[0，inf] 3、Chebyshev–Gauss quadrature切比雪夫 0、Gauss型积分通用形式 The integration problem can be expressed in a slightly more general way b
注意系数为\(0\)的多项式要消去哦 map<int,double,greater<int>> mp; int n; int main() { for(int i=0;i<2;i++) { cin>>n; for(int j=0;j<n;j++) { int p; double a; scanf("%d%lf
https://blog.csdn.net/a845717607/article/details/86530433 map使用： 声明：map<键，值> 变量名； 存储： scanf("%d %lf",&e,&coe); mp1[e]=coe; 遍历：for(map<int,double>::iterator it=mp1.begin();it!=mp1.end();++it) 逆序遍历：for(map<int,doub
1002 A+B for Polynomials (25分) #include<stdio.h> int main() { double a[1010]={0.0},b[1010]={0.0},c[1010]={0.0}; int n1,n2; scanf("%d",&n1); for(int i=0;i<n1;i++){ int a0; scanf("%d",&a0
1009 Product of Polynomials (25分) This time, you are supposed to find A×B where A and B are two polynomials. Input Specification: Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of
1.多项式为0，直接输出0 2.系数为0的项不输出 3.注意double类型的判0 1 #include <iostream> 2 #include <vector> 3 #include <iomanip> 4 #include <cmath> 5 using namespace std; 6 7 int main() 8 { 9 vector<int> a, b;//次数 10 vec
1002 A+B for Polynomials (25分) This time, you are supposed to find A+B where A and B are two polynomials. Input Specification: Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynomial: K N
This time, you are supposed to find A×B where A and B are two polynomials. Input Specification: Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynomial: K N1 aN1 N
多项式加法——MOOC《零基础学习Java语言》 #第五周编程题 多项式加法 注意： 1.多项式全为0，显示0。 2.最高幂次前面不显示加减符号。 3.幂次为1，不显示. 4.系数为1或-1，不显示。 import java.util.Scanner; public class Main { public static void main(String[] args) {
题目描述 This time, you are supposed to find A×B where A and B are two polynomials. 输入格式 Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynomial: K N1 aN1 N2 aN2 … NK aNK w
题目链接 This time, you are supposed to find A+B where A and B are two polynomials. Input Specification: Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynomial: where K is the number o
PAT甲级 1002 A+B for Polynomials This time, you are supposed to find A+B where A and B are two polynomials. Input Specification: Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynomial:
原题 This time, you are supposed to find A+B where A and B are two polynomials. Input Specification: Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynomial: K N1 aN1 N2 aN
题目描述 This time, you are supposed to find A+B where A and B are two polynomials 输入格式 Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynomial: K N1 aN1 N2 aN2 ... NK aNK , where
2019-12-23 14:54:40 #include <bits/stdc++.h> #include<math.h> using namespace std; const int MAX_LEN = 2004; int main(){ double temp1[MAX_LEN]={0}; double temp2[MAX_LEN]={0}; int tem1; cin>>tem1; for(int i =0;i&
