1. Why do I care? In R, when we want to create a new column we often use mutate() function. A little complex situation is that this new column is base on some existing columns such that we have to prepare our logic first. One common solution is using if_
Unit 2 - The Dinner Party A heated discussion about whether men are braver than women is settled in a rather unexpected way. The Dinner Party I first heard this tale in India, where is told as if true -- though any naturalist would know it couldn't b
python 加载CSV文件的两种方法 1、使用python csv模块2、使用np.loadtxt函数使用方法如下 1、使用python csv模块 reader(csvfile, dialect='excel', **fmtparams) 2、使用np.loadtxt函数 loadtxt(fname, dtype=<class 'float'>, comments='#', delimiter=None, conver
前言： 策略模式初学者很少听到，有时候遇到，但是却不清楚是使用该模式实现的功能，我看了一下百度，对这个模式的解释很生硬，其实简单的来说，什么是策略模式呢，比如你去淘宝上买东西，如果你是男生，它的首页会给你推荐男生喜欢的物品，如果你是女生呢，它会给你推荐女生常用的物品，就感觉啊，这个
suggest+名词、动名词短语、句子 suggest后面跟的是建议的事情，具有名词的特性。 比如： I suggest this method. I suggest trying once again. I suggest we have dinner now. we have dinner 这个行为说白了还是一件事情。
原题链接在这里：https://leetcode.com/problems/dinner-plate-stacks/ 题目： You have an infinite number of stacks arranged in a row and numbered (left to right) from 0, each of the stacks has the same maximum capacity. Implement the DinnerPlates class: DinnerP
题目如下： You have an infinite number of stacks arranged in a row and numbered (left to right) from 0, each of the stacks has the same maximum capacity. Implement the DinnerPlates class: DinnerPlates(int capacity) Initializes the object with the maximum
3-1 姓名： 将一些朋友的姓名存储在一个列表中，并将其命名为names 。依次访问该列表中的每个元素，从而将每个朋友的姓名都打印出来。 names = ['ada', 'eric', 'per'] print(names[0]) print(names[1]) print(names[2]) 3-2 问候语： 继续使用练习3-1中的列表，但不打印每个朋友
课上内容（Lesson） What is your favorite food? I llike hotpot. Where is it from? It comes from Shichuan. What's in it? It has all kind of meats , seafoods, vegetables,Bean made food,Mushrooms,Eggs, bean vermicelli etc. When do people eat it (for br
1、发布订阅者模式 //订阅发布平台应该是一个全局的var pubsub={};(function(pubsub){ var topics={}; pubsub.publish=function(topic){ //发布话题，订阅了该话题的都会收到消息 if(!topics[topic]){ //不存在该话题 return; } var funs = topics[topic];
