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  • DDPG:CONTINUOUS CONTROL WITH DEEP REINFORCEMENT LEARNING2021-02-28 17:30:55

    CONTINOUS CONTROL WITH DEEP REINFORCEMENT LEARNING 论文地址 https://arxiv.org/abs/1509.02971 个人翻译,并不权威 Timothy P.Lilicrp,Jonathan J.Hunt,Alexander Pritzel, Nicolas Heess, Tom Erez, Yuval Tassa, David Silver & Daan Wierstra Google Deepmind London,

  • 一篇文章带你搞懂什么是 CI/CD - 持续集成、持续交付、持续部署?2021-02-27 10:31:33

    文章目录 一、持续集成(Continuous Integration)

  • BlueGreenDeployment2021-02-26 17:36:44

    BlueGreenDeployment One of the goals that my colleagues and I urge on our clients is that of a completely automated deployment process. Automating your deployment helps reduce the frictions摩擦 and delays that crop up突然 in between getting the software "

  • 1438. Longest Continuous Subarray With Absolute Diff Less Than or Equal to Limit2021-02-21 23:34:07

    仅供自己学习   也是一种滑动窗口的思想,而左指针右移的条件是子串最大值与最小值之差 > limit时就将left相加。而主要的时间消耗是寻找字串的最大值和最小值,需要一个合适的数据结构。这里用的一个multiset,基于红黑树的平衡搜索二叉树,是可以存放重复的元素的从小到大排列的序列。

  • leetcode小白刷题之旅----674. Longest Continuous Increasing Subsequence2021-01-24 12:01:59

    仅供自己学习   题目: Given an unsorted array of integers nums, return the length of the longest continuous increasing subsequence (i.e. subarray). The subsequence must be strictly increasing. A continuous increasing subsequence is defined by two indices l and

  • Policy Iterations for Reinforcement Learning Problems in Continuous Time and Space—Fundamental Theor2021-01-19 09:34:02

    郑重声明:原文参见标题,如有侵权,请联系作者,将会撤销发布! [Submitted on 9 May 2017 (v1), last revised 31 Oct 2020 (this version, v2)]   Abstract   策略迭代(PI)是策略评估和改进的递归过程,用于解决最优决策/控制问题,换句话说,就是RL问题。PI也是开发RL方法的基础。在本文中

  • 持续集成 CI,CD2021-01-16 09:33:23

    持续集成Continuous Integration 持续集成是指开发者在代码的开发过程中,可以频繁的将代码部署集成到主干,并进行自动化测试 持续交付Continuous Delivery 持续交付指的是在持续集成的环境基础之上,将代码部署到预生产环境 持续部署Continuous Deployment 在持续交付的基础上,把

  • Docker教程2020-12-26 15:02:35

    关键点 基于 Go 语言编写 ,遵从 Apache2.0 协议开源 是一种容器,采用沙箱机制,类似iPhone的app 轻量级虚拟机,微服务,轻巧,资源开销低 高度可移植:你制作好的容器镜像,可以随意拿到一个安装了Docker引擎的主机上运行起来,无论你是本地PC虚拟机,数据中心机房的服务器物理机或者虚拟机,各大厂商

  • 523. Continuous Subarray Sum 起止点是K的倍数2020-10-31 05:32:05

    Given a list of non-negative numbers and a target integer k, write a function to check if the array has a continuous subarray of size at least 2 that sums up to a multiple of k, that is, sums up to n*k where n is also an integer.   Example 1: Input: [2

  • Unity_Rigidbody2020-10-14 08:03:27

    Unity_Rigidbody Rigidbody:刚体,可以使游戏对象在物理系统的控制下进行运动。多用于游戏对象在现实世界中的物理特性。 注意:通常在OnFixedUpdate()中执行Rigidbody类,因为物理相关计算一般需要在固定时间间隔内进行计算。 注意:当rigidbody接管了物体的运动时,不应该对物体进行Trasnsf

  • [LeetCode] 581. Shortest Unsorted Continuous Subarray2020-09-19 08:04:47

    Given an integer array, you need to find one continuous subarray that if you only sort this subarray in ascending order, then the whole array will be sorted in ascending order, too. You need to find the shortest such subarray and output its length. Examp

  • 228. Summary Ranges2020-09-06 15:33:56

    package LeetCode_228 /** * 228. Summary Ranges * https://leetcode.com/problems/summary-ranges/description/ * Given a sorted integer array without duplicates, return the summary of its ranges. Example 1: Input: [0,1,2,4,5,7] Output: ["0->2&quo

  • 什么是"continuous delivery pipline"其实是描述项目软件控制流程2020-09-05 14:01:31

    目前最大的限制是属性必须是可变的(译者注:即可写的),对象初始化器才能工作:它们首先调用对象的构造函数(本例中是默认的无参数构造函数),然后赋值给属性 setter。 仅初始化(init-only)属性解决了这个问题!它引入了一个 init 访问器,它是 set 访问器的变体,只能在对象初始化时调用: public c

  • reactjs——Continuous Integration2020-04-08 12:00:36

    https://www.newline.co/fullstack-react/30-days-of-react/day-29/ Continuous Integration Today we'll look through some continuous integration solutions available for us to run tests against as well as implement one to test our application in the cloud.

  • 18.基于K8S的PaaS概述2020-02-04 15:50:53

    CI:Continuous Integration 持续集成 CD:Continuous Deployment持续部署 CD:Continuous Delivery持续交付  一、流程: 持续集成工具:Jenkins,Go CD 构建工具:maven,make 测试工具:Jmeter 扫描工具:sonar 部署工具:Ansible,SaltStack,Chef,Puppet等 配置管理工具: 工件仓库:Jfrag, docker hub 版本

  • Jenins 介绍2020-01-31 10:51:40

    Jenins    Jenins 是一个用来帮助运维研发生命周期提高效率的BS架构的管理软件,功能强大提供多种扩展模块来完成一系列工作,Jenkins 主要可以根据相关环境对运维人员减少频繁的人力工作,减少失误,减少人力消耗,提高工作效率与质量   CI/CD,DevOps 持续集成(Continuous Integration,CI

  • Longest Continuous Increasing Subsequence2019-12-21 20:54:10

    Description Give an integer array,find the longest increasing continuous subsequence in this array. An increasing continuous subsequence: Can be from right to left or from left to right. Indices of the integers in the subsequence should be continuous.

  • I4-6 Present continuous Teacher: Lamb2019-11-03 17:56:11

    课上内容(Lesson) 1. We played "Who is spy" together  2.  Which county do you like it, let us make a choice.  3. We made use of picturea for a story , about a woman is exercising in the park. 4. We drew about other group talked us story and show 5. E

  • 【2019银川网络赛】L:Continuous Intervals2019-09-03 15:50:52

    题目大意:给定一个长度为 N 的序列,定义连续区间 [l, r] 为:序列的一段子区间,满足 [l, r] 中的元素从小到大排序后,任意相邻两项的差值不超过1。求一共有多少个连续区间。 题解:单调栈 + 线段树 首先,对于区间计数类问题常规的思路是枚举区间的左端点或右端点,统计以该点为端点的区间个数

  • The 2019 Asia Yinchuan First Round Online Programming L. Continuous Intervals —— 线段树2019-08-31 20:41:42

    This way 题意: 给你一个数组,一个区间视为有效的当且仅当这个区间排序之后,任意两个连续的数的差的绝对值不超过1,问你有多少个有效的区间 题解: 今天又是莫干山吗。。。 这个题意翻译一下就是:区间最大值-区间最小值+1=区间不同值的个数 那么我们用线段树维护最大值-最小值-不

  • Continuous Intervals Gym - 102222L(2018宁夏邀请赛暨2019银川icpc网络预选赛)2019-08-31 20:02:10

    Lamis is a smart girl. She is interested in problems about sequences and their intervals. Here she shows you a sequence of length nn with positive integers, denoted by a1,a2,a3,⋯,ana1,a2,a3,⋯,an. She is amazed at those intervals, which is a consecuti

  • javascript – JS计数器不断更新2019-07-23 09:37:46

    How to implement a live and persistent number counter on a site 所以我在看这个问题(^),我想做同样的事情,除了一点点不同. 我需要其中一个从麻木的138,276,343美元起每秒15.8美分 我希望逗号像正常的金额一样. 我能用这种方式工作吗?我很难过.就像上面问题的海报一样,我没有太

  • Continuous Same Game (1) 简单的模拟dfs() 很好过2019-06-30 11:56:24

    Problem Description Continuous Same Game is a simple game played on a grid of colored blocks. Groups of two or more connected (orthogonally, not diagonally) blocks that are the same color may be removed from the board. When a group of blocks is removed, t

  • 在python中连续循环和退出2019-06-26 22:43:36

    我有一个脚本,在调用时连续运行,每5分钟检查一次我的Gmail收件箱.为了让它每5分钟运行一次,我使用的是time.sleep()函数.但是我希望用户在按下q时随时结束脚本,这在使用time.sleep()时似乎无法完成.关于我如何做到这一点的任何建议? 阿里解决方法:您可以在sys.stdin上使用select()并

  • 从Python调用Perl脚本不断返回值2019-06-25 15:45:42

    我在这个网站上发现了一个问题,告诉我如何从Python调用Perl脚本.我目前正在使用以下代码行来实现这个目的: pipe = subprocess.Popen(["perl", "./Perl_Script.pl", param], stdout=subprocess.PIPE) result = pipe.stdout.read() 这很好用,但唯一的问题是Perl脚本需要几分钟才能

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