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  • LeetCode笔记:Biweekly Contest 55(补发)2021-07-07 20:02:53

    LeetCode笔记:Biweekly Contest 55 1. 题目一 1. 解题思路2. 代码实现 2. 题目二 1. 解题思路2. 代码实现 3. 题目三 1. 解题思路2. 代码实现 4. 题目四 1. 解题思路2. 代码实现 1. 题目一 给出题目一的试题链接如下: 1909. Remove One Element to Make the Array Strictly I

  • 2021 Hubei Provincial Collegiate Programming Contest2021-07-07 16:02:35

    D. Fragmentation merging D. Fragmentation merging  题意:自己看 题解:对每一种情况进行判断,看是不是由最多两段组成就行了 AC代码 #include "bits/stdc++.h" using namespace std; #define ll long long const int maxn=5e3+10; const int inf=0x3f3f3f3f; inline int rd(){

  • 2020-2021 “Orz Panda” Cup Programming Contest2021-07-04 18:00:25

    2020-2021 “Orz Panda” Cup Programming Contest A. Accordion Artist And Orz Pandas 题意 给定\(n\)个相邻的矩形,矩形的宽和高给定,问最大的子矩形面积 分析 单调栈板题,维护出每个矩形左边第一个比他低的点和右边第一个比它低的点,两点距离就是宽,高就是当前矩形的高,维护宽X高的

  • Atcoder Grand Contest 008 E - Next or Nextnext(乱搞+找性质)2021-07-03 18:35:21

    Atcoder 题面传送门 & 洛谷题面传送门 震惊,我竟然能独立切掉 AGC E 难度的思维题! hb:nb tea 一道 感觉此题就是找性质,找性质,再找性质( 首先看到排列有关的问题,我们可以很自然地将排列拆成一个个置换环,即我们建一张图 \(G\),对于 \(i\in[1,n]\) 连边 \(i\to p_i\),那么题目的要求就可以

  • 2020 ECNU Campus Online Invitational Contest2021-07-03 11:00:39

    E. Even Degree Problem - E - Codeforces   找出欧拉图的欧拉回路,并将路径都存入数组中,计第一位l=1最后一位r=top(top为改欧拉图的边数) 找欧拉回路的操作:   从任意一点开始dfs,dfs的途中删除已经遍历过的边减小搜索规模,具体操作每次便利前向星的时候不让i直接等于e[i].next而是

  • HZNU-AlternatingCat 训练实录2021-07-02 20:01:49

    HZNU-AlternatingCat 训练实录 现场赛记录:[名称:奖项/排名] 2021: The 2021 ICPC China Shaanxi National Invitational Programming Contest : Silver/83 To do list: 暑假每周坚持五训,尽量在当天和第二天补完题 学习金牌难度算法,不要畏难 多校认真打,当成正式比赛 我加强数学(以

  • LeetCode contest 1022021-06-29 13:54:27

    https://leetcode-cn.com/contest/weekly-contest-102/problems/sort-array-by-parity/ 水题 我的解决方案: class Solution { public int[] sortArrayByParity(int[] A) { int[] B = new int[A.length]; int cnt=0; for(int i=0;i<A.length;i++) {

  • COCI2015/2016 Contest#4 D2021-06-26 20:00:52

    COCI2015/2016 Contest#4 D 题意: ​ 给出一个有 \(n\) 个节点的 \(k\) 叉树. \(k\) 叉树是指每个点最多有 \(k\) 个儿子的树(每一条边权值为1).每个节点的编号就是该节点加入树的顺序,每个节点从左往右添加到树中,节点 \(x\) 的深度增加当且仅当在它左边的每个节点都已经被填满了

  • OI迷惑行为大赏2021-06-17 21:03:11

    AtCoder Beginner Contest 165 問題の不備が発見されたため、10分間開始を遅らせます。申し訳ありません。 / The start will be delayed for 10 minutes due to an inadequacy discovered in the problem. I'm sorry.

  • 【Virtual Judge】The 2019 China Collegiate Programming Contest Harbin Site-Keeping Rabbits2021-06-17 18:53:05

    Keeping Rabbits DreamGrid is the keeper of n rabbits. Initially, the i-th (1≤i≤n) rabbit has a weight of wi. Every morning, DreamGrid gives the rabbits a carrot of weight 1 and the rabbits fight for the only carrot. Only one rabbit wins the fight and ea

  • 【Virtual Judge】The 2019 China Collegiate Programming Contest Harbin Site J—Justifying the Conjecture2021-06-17 18:52:57

    Justifying the Conjecture time limit per test1 second memory limit per test512 megabytes inputstandard input outputstandard output The great mathematician DreamGrid proposes a conjecture, which states that: Every positive integer can be expressed as the

  • The 2020 ICPC Asia Macau Regional Contest B Boring Problem2021-06-13 02:03:25

    比较模板的题。 题目 给定一个字符串 \(S\),\(n\) 个字符串 \(T_1,T_2,\dots,T_n\),每个串长度都是 \(m\),一个长度为 \(k\) 的有理数序列 \(p_1,p_2,\dots,p_k\) 保证 \(\sum p_i=1\)。每个字符串由前 \(k\) 个小写字母构成。 我们进行下面的过程: 如果存在 \(j(1\le j\le n)\) 满足

  • LeetCode笔记:Weekly Contest 243 比赛记录2021-06-08 21:00:40

    LeetCode笔记:Weekly Contest 243 LeetCode笔记:Weekly Contest 243 1. 题目一 1. 解题思路2. 代码实现 2. 题目二 1. 解题思路2. 代码实现 3. 题目三 1. 解题思路2. 代码实现 4. 题目四 1. 解题思路2. 代码实现 1. 题目一 给出题目一的试题链接如下: 1880. Check if Word Equ

  • NOMURA Programming Contest 2021(AtCoder Regular Contest 121)2021-06-02 22:34:59

    C.Odd Even Sort 题目描述 点此看题 有一个长度为 \(n\) 的排列,要求通过 \(n^2\) 次操作把他变成 \(1,2...n\) 的排列: 奇数次操作可以操作奇数位置 \(x\),即交换 \(p[x],p[x+1]\) 偶数次操作可以操作偶数位置 \(x\),即交换 \(p[x],p[x+1]\) \(n\leq 500\) 解法 \(n^2\) 次操作这么

  • Leetcode Weekly Contest 243(详细解析)2021-06-01 21:02:12

    题目链接: Leetcode Weekly Contest 243 写在前面: 本次周赛做出了前两题。 1、1880. Check if Word Equals Summation of Two Words 难度:Easy 题目大意: 将字符串按照题意规则转化成相应的值。 思路: 模拟即可 。 代码 class Solution { public boolean isSumEqual(String f

  • AISing Programming Contest 2021(AtCoder Beginner Contest 202) E - Count Descendants (dfs,思维)2021-06-01 02:32:20

    题意:有一颗树,根结点为\(1\).\(q\)个询问,每次问你共有多少经过\(u\)点且到根节点距离为\(d\)的点. 题解:这题技巧性好强,我们从根节点遍历整颗树,用时间轴记录搜到和离开的时间\(in_i\)和\(out_i\),同时存入同一深度的所有\(in_i\),方便后面计算.对于某个父亲结点\(u\),它

  • 【杭电多校4】2020 Multi-University Training Contest 42021-05-24 12:52:36

      Blow up the Enemy     #include <bits/stdc++.h> #define rep(i,a,b) for(int i=a;i<b;i++) #define T ll t ;scanf("%lld",&t);while(t--) using namespace std ; typedef long long ll; typedef unsigned long long ull; const ll maxn=1e5+10;

  • AISing Programming Contest 2021(AtCoder Beginner Contest 202)D.aab aba baa2021-05-23 20:06:03

    题目链接 Problem Statement Among the strings of length A+B containing A occurrences of a and B occurrences of b, find the string that comes K-th in the lexicographical order. Sample Input 1 2 2 4 Sample Output 1 baab Sample Input 2 30 30 11826458156486

  • 2016-2017 ACM Central Region of Russia Quarterfinal Programming Contest B. Hanoi tower2021-05-23 16:35:18

    原题 Gym 101243B It has become a good tradition to solve the “Hanoi tower” puzzle at programming contests in Rybinsk. We will review the rules briefly. There are 3 rods marked A, B, C. Initially, N disks of different diameter are placed on rod A: the smalle

  • E. The Contest(调整成递增序列)2021-05-23 14:58:48

    https://codeforces.com/problemset/problem/1257/E 思路:lis二分板子 #include<iostream> #include<vector> #include<queue> #include<cstring> #include<cmath> #include<map> #include<set> #include<cstdio> #include<alg

  • 梦开始的地方2021-05-21 12:01:26

    AtCoder Grand Contest 017 2020年了。 时隔2年半,在时间长河的下游,凝视着,最开始的篇章。 AtCoder说,我的Performance是1700。 于是,我的Rating从17涨到了493。 那是无忧无虑的日子,基本每周有比赛,我一定参加。 在家里,在外地。在书桌前,在火车上。用电脑,用iPad。 从最开始的Python 2,逐

  • The 2019 ACM-ICPC China Shannxi Provincial Programming Contest2021-05-19 16:36:28

    A - Tasks dp或者贪心 #define x first #define y second #define pb push_back #define ls rt << 1 #define rs rt << 1 | 1 typedef long long ll ; const double esp = 1e-6 , pi = acos(-1) ; typedef pair<int , int> PII ; const int N = 1e6 + 10 , INF

  • iOS 审核被拒:5.3.2 -合法-赌博,赌博和彩票2021-05-14 10:33:12

    反馈邮件: Guideline 5.3.2 - Legal - Gaming, Gambling, and Lotteries Your app includes a contest or sweepstakes but it does not: - Indicate that Apple is not involved in any way with the contest or sweepstakes. Next Steps It is necessary to: - Include o

  • 2020 China Collegiate Programming Contest, Weihai Site H. Message Bomb(差分/思维/好题)2021-05-12 02:03:23

    While we enjoy chatting with friends on the internet, it is always annoying that we are overwhelmed by lots of messages in various chat groups. A great majority of these messages are actually not interesting to us, but we may miss some important notices i

  • 300iq Contest 2【杂题】2021-05-11 21:36:16

    传送门:link D Determinant 给定 \(n\) 个点 \(m\) 条边的简单连通无向图,求邻接矩阵行列式\(\bmod 998244353\)。 \(n\le 2.5\cdot 10^4\),\(m\le 5\cdot 10^5\),\(\exist k\in\{1,2,\cdots,25\}\),\(\forall A\subseteq V\land |A|=k+1\),\(\exist a,b\in A\),\(e\in

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