标签:专题 int kuangbin mid y1 board 几何 x2 x1
思路:二分。
#include<iostream> #include<cstdio> #include<cstring> using namespace std; const int maxn = 5005; int n, m, x1, y1, x2, y2; int box[maxn]; struct Board{ int x1, x2; } board[maxn]; bool onLeft(int idx, int x, int y){ Board &b = board[idx]; return (b.x2 - b.x1) * (y - y1) - (y2 - y1) * (x - b.x1) < 0; } int findPosition(int x, int y){ int l = 0, r = n + 1; while(l + 1 != r){ int mid = (l + r) >> 1; if (onLeft(mid, x, y)) r = mid; else l = mid; } return l; } int main(){ while(scanf("%d", &n) && n){ memset(box, 0, sizeof(box)); scanf("%d%d%d%d%d", &m, &x1, &y1, &x2, &y2); board[0].x1 = board[0].x2 = x1; board[n+1].x1 = board[n+1].x2 = x2; for(int i = 1; i <= n; i++) scanf("%d%d", &board[i].x1, &board[i].x2); for(int i = 0; i < m; i++) { int x, y; scanf("%d%d", &x, &y); int position = findPosition(x, y); box[position]++; } for(int i = 0; i <= n; i++) printf("%d: %d\n", i, box[i]); printf("\n"); } return 0; }View Code
POJ2398 Toy Storage
思路:同上,记得给挡板排序。
#include<iostream> #include<cstdio> #include<cstring> #include<algorithm> using namespace std; const int maxn = 5005; int n, m, x1, y1, x2, y2; int box[maxn]; struct Cnt{ int cnt, idx; } cnt[maxn]; struct Board{ int x1, x2; } board[maxn]; bool onLeft(int idx, int x, int y){ Board &b = board[idx]; return (b.x2 - b.x1) * (y - y1) - (y2 - y1) * (x - b.x1) < 0; } int findPosition(int x, int y){ int l = 0, r = n + 1; while(l + 1 != r){ int mid = (l + r) >> 1; if (onLeft(mid, x, y)) r = mid; else l = mid; } return l; } bool cmpBoard(const Board& b1, const Board& b2){ if(b1.x1 == b2.x1) return b1.x2 < b2.x2; return b1.x1 < b2.x1; } int main(){ while(scanf("%d", &n) && n){ memset(box, 0, sizeof(box)); memset(cnt, 0, sizeof(cnt)); scanf("%d%d%d%d%d", &m, &x1, &y1, &x2, &y2); board[0].x1 = board[0].x2 = x1; board[n+1].x1 = board[n+1].x2 = x2; for(int i = 1; i <= n; i++) scanf("%d%d", &board[i].x1, &board[i].x2); sort(board, board + n + 2, cmpBoard); for(int i = 0; i < m; i++) { int x, y; scanf("%d%d", &x, &y); int position = findPosition(x, y); box[position]++; } for(int i = 0; i <= n; i++){ cnt[box[i]].cnt++; } printf("Box\n"); for(int i = 1; i <= m; i++) if(cnt[i].cnt) printf("%d: %d\n", i, cnt[i].cnt); } return 0; }View Code
标签:专题,int,kuangbin,mid,y1,board,几何,x2,x1 来源: https://www.cnblogs.com/arch/p/14724229.html
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