ICode9

精准搜索请尝试: 精确搜索
首页 > 其他分享> 文章详细

Traverse an expression tree and extract parameters

2019-09-24 19:00:44  阅读:281  来源: 互联网

标签:Traverse declaringType Visit tree what propertyNames expr extract public


Traverse an expression tree and extract parameters

 

I think as you've said that using ExpressionVisitor works out to be a good approach. You don't need to implement all the Visit... methods as they already have a default implementation. From what I understood what you want is to find all property accesses of a certain type inside a lambda function

public class MemberAccessVisitor : ExpressionVisitor
{
    private readonly Type declaringType;
    private IList<string> propertyNames = new List<string>();

    public MemberAccessVisitor(Type declaringType)
    {
        this.declaringType = declaringType;
    }

    public IEnumerable<string> PropertyNames { get { return propertyNames; } }

    public override Expression Visit(Expression expr)
    {
        if (expr != null && expr.NodeType == ExpressionType.MemberAccess)
        {
            var memberExpr = (MemberExpression)expr;
            if (memberExpr.Member.DeclaringType == declaringType)
            {
                propertyNames.Add(memberExpr.Member.Name);
            }
        }

        return base.Visit(expr);
    }
}

This could be further improved to what you want by checking the member is a property and also to get PropertyInfo rather than strings

It could be used as follows:

var visitor = new MemberAccessVisitor(typeof(TSource));

visitor.Visit(memberMap);

var propertyNames = visitor.PropertyNames;

 

标签:Traverse,declaringType,Visit,tree,what,propertyNames,expr,extract,public
来源: https://www.cnblogs.com/chucklu/p/11580209.html

本站声明: 1. iCode9 技术分享网(下文简称本站)提供的所有内容,仅供技术学习、探讨和分享;
2. 关于本站的所有留言、评论、转载及引用,纯属内容发起人的个人观点,与本站观点和立场无关;
3. 关于本站的所有言论和文字,纯属内容发起人的个人观点,与本站观点和立场无关;
4. 本站文章均是网友提供,不完全保证技术分享内容的完整性、准确性、时效性、风险性和版权归属;如您发现该文章侵犯了您的权益,可联系我们第一时间进行删除;
5. 本站为非盈利性的个人网站,所有内容不会用来进行牟利,也不会利用任何形式的广告来间接获益,纯粹是为了广大技术爱好者提供技术内容和技术思想的分享性交流网站。

专注分享技术,共同学习,共同进步。侵权联系[81616952@qq.com]

Copyright (C)ICode9.com, All Rights Reserved.

ICode9版权所有