标签:797 Paths node Target graph back vector ans path
Given a directed acyclic graph (DAG) of n nodes labeled from 0
to n - 1
, find all possible paths from node 0
to node n - 1
and return them in any order.
The graph is given as follows: graph[i]
is a list of all nodes you can visit from node \(i\) (i.e., there is a directed edge from node \(i\) to node graph[i][j]
).
Solution
求一个点到终点的每条路径。对于边的存储我们依然是用 \(vector\),为了遍历每一种情况,在 \(DFS\) 的时候,记得 \(pop\_back\)
点击查看代码
class Solution {
private:
vector<vector<int>> ans;
void dfs(int from, int tgt, vector<vector<int>> graph, vector<int>& path, vector<vector<int>>& ans){
path.push_back(from);
if(from==tgt){
ans.push_back(path); return;
}
for(auto to: graph[from]){
dfs(to, tgt, graph, path, ans);
path.pop_back();
}
}
public:
vector<vector<int>> allPathsSourceTarget(vector<vector<int>>& graph) {
int sz = graph.size();
vector<int> path;
dfs(0, sz-1, graph, path, ans);
return ans;
}
};
标签:797,Paths,node,Target,graph,back,vector,ans,path 来源: https://www.cnblogs.com/xinyu04/p/16558362.html
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