标签:Binary Search return target nums 704 min mid int
Given an array of integers nums which is sorted in ascending order, and an integer target, write a function to search target in nums. If target exists, then return its index. Otherwise, return -1.
You must write an algorithm with O(log n) runtime complexity.
Example 1:
Input: nums = [-1,0,3,5,9,12], target = 9
Output: 4
Explanation: 9 exists in nums and its index is 4
Example 2:
Input: nums = [-1,0,3,5,9,12], target = 2
Output: -1
Explanation: 2 does not exist in nums so return -1
Constraints:
1 <= nums.length <= 104
-104 < nums[i], target < 104
All the integers in nums are unique.
nums is sorted in ascending order.
solution:
class Solution {
public:
int search(vector<int>& nums, int target) {
int min = 0;
int mid = nums.size()/2;
int max = nums.size();
while(target != nums[mid])
{
if(max < min)
{
return -1;
}
if(nums[mid] == target)
{
return mid;
}else if(nums[mid] > target){
max = mid - 1;
mid = min + (max - min)/2;
}else if(nums[mid] < target){
min = mid + 1;
mid = min + (max - min)/2;
}
if(mid > nums.size()-1)
{
return -1;
}
}
return mid;
}
};
标签:Binary,Search,return,target,nums,704,min,mid,int 来源: https://www.cnblogs.com/Pomelos/p/15765261.html
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