标签:sqlite for-loop substring sql android
我有一个包含一串数字的字段
"2002 2005 2001 2006 2008 2344"
最好我们假设空格是分割线,否则,假设每个空格长度为4个字符.
我可以选择一个子字符串:
SELECT substr(years,1,4) FROM TABLE
但是不知道如何检查每个.我试图找到包含最接近0的数字的行.
我可以按BYDER和LIMIT 1订购.
解决方法:
这看起来很丑陋,但是它在一个SQLlite语句中选择了您需要的所有内容.如果假设日期在当前时间间隔内,例如1900..2100,您也可以进行一些优化.在这种情况下,您可以先剪切2个选择B,C(B:1联合2)(C:9联合0联合1)
select years2,years from
(
select i1||i2||i3||i4 as years2 from (select '0' as i1
union all
select '1' as i1
union all
select '2' as i1
union all
select '3' as i1
union all
select '4' as i1
union all
select '5' as i1
union all
select '6' as i1
union all
select '7' as i1
union all
select '8' as i1
union all
select '9' as i1) B,
(select '0' as i2
union all
select '1' as i2
union all
select '2' as i2
union all
select '3' as i2
union all
select '4' as i2
union all
select '5' as i2
union all
select '6' as i2
union all
select '7' as i2
union all
select '8' as i2
union all
select '9' as i2) C,
(select '0' as i3
union all
select '1' as i3
union all
select '2' as i3
union all
select '3' as i3
union all
select '4' as i3
union all
select '5' as i3
union all
select '6' as i3
union all
select '7' as i3
union all
select '8' as i3
union all
select '9' as i3) D,
(select '0' as i4
union all
select '1' as i4
union all
select '2' as i4
union all
select '3' as i4
union all
select '4' as i4
union all
select '5' as i4
union all
select '6' as i4
union all
select '7' as i4
union all
select '8' as i4
union all
select '9' as i4) E
) YearsAll
left join YearsTable on (YearsTable.years like '%'||YearsAll.years2||'%')
where YearsTable.years is not null
order by years2 limit 1
标签:sqlite,for-loop,substring,sql,android 来源: https://codeday.me/bug/20191201/2077381.html
本站声明: 1. iCode9 技术分享网(下文简称本站)提供的所有内容,仅供技术学习、探讨和分享; 2. 关于本站的所有留言、评论、转载及引用,纯属内容发起人的个人观点,与本站观点和立场无关; 3. 关于本站的所有言论和文字,纯属内容发起人的个人观点,与本站观点和立场无关; 4. 本站文章均是网友提供,不完全保证技术分享内容的完整性、准确性、时效性、风险性和版权归属;如您发现该文章侵犯了您的权益,可联系我们第一时间进行删除; 5. 本站为非盈利性的个人网站,所有内容不会用来进行牟利,也不会利用任何形式的广告来间接获益,纯粹是为了广大技术爱好者提供技术内容和技术思想的分享性交流网站。