标签:Even 1315 Valued right ans grandparent nodes root left
Given a binary tree, return the sum of values of nodes with even-valued grandparent. (A grandparent of a node is the parent of its parent, if it exists.)
If there are no nodes with an even-valued grandparent, return 0
.
Example 1:
Input: root = [6,7,8,2,7,1,3,9,null,1,4,null,null,null,5] Output: 18 Explanation: The red nodes are the nodes with even-value grandparent while the blue nodes are the even-value grandparents.
Constraints:
- The number of nodes in the tree is between
1
and10^4
. - The value of nodes is between
1
and100
.
class Solution { public: int sumEvenGrandparent(TreeNode* root) { if(!root) return 0; int ans=0; if(root->val%2==0){ if(root->left){ if(root->left->left) ans+=root->left->left->val; if(root->left->right) ans+=root->left->right->val; } if(root->right){ if(root->right->left) ans+=root->right->left->val; if(root->right->right) ans+=root->right->right->val; } } return ans+sumEvenGrandparent(root->left)+sumEvenGrandparent(root->right); } };
标签:Even,1315,Valued,right,ans,grandparent,nodes,root,left 来源: https://www.cnblogs.com/Makerr/p/14671134.html
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