标签:index ab Java Anagrams int substring start anagram Find
Leetcode.438 Find All Anagrams in a String
Given a string s and a non-empty string p, find all the start indices of p's anagrams in s.
Strings consists of lowercase English letters only and the length of both strings s and p will not be larger than 20,100.
The order of output does not matter.
Example 1:
Input:
s: "cbaebabacd" p: "abc"
Output:
[0, 6]
Explanation:
The substring with start index = 0 is "cba", which is an anagram of "abc".
The substring with start index = 6 is "bac", which is an anagram of "abc".
Example 2:
Input:
s: "abab" p: "ab"
Output:
[0, 1, 2]
Explanation:
The substring with start index = 0 is "ab", which is an anagram of "ab".
The substring with start index = 1 is "ba", which is an anagram of "ab".
The substring with start index = 2 is "ab", which is an anagram of "ab".
Solution
class Solution {
public List<Integer> findAnagrams(String s, String p) {
int sl = s.length();
int pl = p.length();
if(sl < pl){
return new ArrayList<>();
}
int[] freq = new int[26];
for(int i=0;i<pl;i++){
freq[p.charAt(i) - 'a']++;
}
// [l,r]
int l = 0;
int r = -1;
int co = p.length();
List<Integer> res = new ArrayList<>();
while(r+1 < sl){
if(freq[s.charAt(r+1) - 'a'] > 0){
freq[s.charAt(++r) - 'a']--;
co--;
}else{
// co控制满足条件的情况,当遇到不满足的时候
freq[s.charAt(l++) - 'a']++;
co++;
}
if(co == 0){
res.add(l);
}
}
return res;
}
}
标签:index,ab,Java,Anagrams,int,substring,start,anagram,Find 来源: https://www.cnblogs.com/xm08030623/p/13475896.html
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