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我可以避免Python中的线程化UDP套接字丢弃数据吗?

2019-12-10 06:57:24  阅读:329  来源: 互联网

标签:multithreading sockets gtk pygtk python


首先,我是Python的新手,正在学习这份工作,所以要保持谦虚!

我正在尝试为Windows编写一个线程化的Python应用程序,该应用程序从UDP套接字(线程1)读取数据,将其写入文件(线程2),并将实时数据(线程3)显示到小部件(gtk)图片使用gtk.gdk.pixbuf).我正在使用队列在线程之间传递数据.

我的问题是,如果我仅启动线程1和3(因此现在跳过文件写入),似乎在前几个样本之后我丢失了一些数据.滴下之后看起来不错.即使在运行线程3之前让线程1完成,这种明显的下降仍然存在.

对于代码段的长度表示歉意(我已经删除了写入文件的线程),但是我觉得删除代码只会提示问题.希望有人可以阐明:-)

import socket
import threading
import Queue
import numpy
import gtk
gtk.gdk.threads_init()
import gtk.glade
import pygtk


class readFromUDPSocket(threading.Thread):

    def __init__(self, socketUDP, readDataQueue, packetSize, numScans):
        threading.Thread.__init__(self)
        self.socketUDP = socketUDP
        self.readDataQueue = readDataQueue
        self.packetSize = packetSize
        self.numScans = numScans

    def run(self):
        for scan in range(1, self.numScans + 1):
            buffer = self.socketUDP.recv(self.packetSize)
            self.readDataQueue.put(buffer)
        self.socketUDP.close()
        print 'myServer finished!'


class displayWithGTK(threading.Thread):

    def __init__(self, displayDataQueue, image, viewArea):
        threading.Thread.__init__(self)
        self.displayDataQueue = displayDataQueue
        self.image = image
        self.viewWidth = viewArea[0]
        self.viewHeight = viewArea[1]
        self.displayData = numpy.zeros((self.viewHeight, self.viewWidth, 3), dtype=numpy.uint16)

    def run(self):
        scan = 0
        try:
            while True:
                if not scan % self.viewWidth: scan = 0
                buffer = self.displayDataQueue.get(timeout=0.1)
                self.displayData[:, scan, 0] = numpy.fromstring(buffer, dtype=numpy.uint16)
                self.displayData[:, scan, 1] = numpy.fromstring(buffer, dtype=numpy.uint16)
                self.displayData[:, scan, 2] = numpy.fromstring(buffer, dtype=numpy.uint16)
                gtk.gdk.threads_enter()
                self.myPixbuf = gtk.gdk.pixbuf_new_from_data(self.displayData.tostring(), gtk.gdk.COLORSPACE_RGB,
                                                        False, 8, self.viewWidth, self.viewHeight, self.viewWidth * 3)
                self.image.set_from_pixbuf(self.myPixbuf)
                self.image.show()
                gtk.gdk.threads_leave()
                scan += 1
        except Queue.Empty:
            print 'myDisplay finished!'
            pass


def quitGUI(obj):
    print 'Currently active threads: %s' % threading.enumerate()
    gtk.main_quit()


if __name__ == '__main__':

    # Create socket (IPv4 protocol, datagram (UDP)) and bind to address
    socketUDP = socket.socket(socket.AF_INET, socket.SOCK_DGRAM)
    host = '192.168.1.5'
    port = 1024
    socketUDP.bind((host, port))

    # Data parameters
    samplesPerScan = 256
    packetsPerSecond = 1200
    packetSize = 512
    duration = 1  # For now, set a fixed duration to log data
    numScans = int(packetsPerSecond * duration)

    # Create array to store data
    data = numpy.zeros((samplesPerScan, numScans), dtype=numpy.uint16)

    # Create queue for displaying from
    readDataQueue = Queue.Queue(numScans)

    # Build GUI from Glade XML file
    builder = gtk.Builder()
    builder.add_from_file('GroundVue.glade')
    window = builder.get_object('mainwindow')
    window.connect('destroy', quitGUI)
    view = builder.get_object('viewport')
    image = gtk.Image()
    view.add(image)
    viewArea = (1200, samplesPerScan)

    # Instantiate & start threads
    myServer = readFromUDPSocket(socketUDP, readDataQueue, packetSize, numScans)
    myDisplay = displayWithGTK(readDataQueue, image, viewArea)

    myServer.start()
    myDisplay.start()

    gtk.gdk.threads_enter()
    gtk.main()
    gtk.gdk.threads_leave()
    print 'gtk.main finished!'

解决方法:

UDP不会验证目标是否收到了它(就像TCP一样)-如果要确保所有数据都到达,则必须在应用程序中实现重传.您控制发送UDP源吗?

标签:multithreading,sockets,gtk,pygtk,python
来源: https://codeday.me/bug/20191210/2099907.html

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