我想使用日期范围和复选框过滤数据.它适用于复选框,但我在为日期范围添加一些查询时遇到此错误.
Warning: mysql_num_rows() expects parameter 1 to be resource, boolean
given in C:\xampp\htdocs\BMJSGCR\1\dt_rtrend1.php on line 51Warning: mysqli_fetch_array() expects parameter 1 to be mysqli_result,
boolean given in C:\xampp\htdocs\BMJSGCR\1\dt_rtrend1.php on line 58
是否可以使用过滤器daterange？因为我在数据库中使用类型数据datetime.
这是我的代码
<?php
if (isset($_POST['chk'])) {
$defect_query = "";
foreach ($_POST['chk'] as $id => $data) {
$defect_query = $defect_query . ", COUNT(CASE t_transaction.DEFECT_CLASS_ID WHEN " . $data . " THEN t_defect_class.DEFECT_CLASS_NAME END) AS `" . $data . "`";
}
//$machine = $_POST['machine'];
$start_date = $_POST['start_date'];
$end_date = $_POST['end_date'];
//$grade = $_POST['grade'];
$chk = $_POST['chk'];
?>
<thead>
<th class="text-center" >Date Process</th>
<?php
foreach ($_POST['chk'] as $id => $data) {
$get_defect_name = mysqli_query($mysqli, "SELECT * FROM `t_defect_class` WHERE `DEFECT_CLASS_ID` = $data");
$defect_name_table = mysqli_fetch_assoc($get_defect_name);
?>
<th class="text-center"><?php echo $defect_name_table['DEFECT_CLASS_NAME']; ?></th>
<?php } ?>
</thead>
<?php
$modal = mysqli_query($mysqli, "SELECT t_name_file.PROCESS_TIME" . $defect_query . " FROM t_transaction INNER JOIN t_name_file ON t_transaction.NAMEFILE_ID=t_name_file.NAMEFILE_ID INNER JOIN t_defect_class ON t_transaction.DEFECT_CLASS_ID=t_defect_class.DEFECT_CLASS_ID GROUP BY t_transaction.DEFECT_CLASS_ID, t_name_file.PROCESS_TIME t_name_file.PROCESS_TIME BETWEEN '$start_date' AND '$end_date' ORDER BY t_name_file.PROCESS_TIME");
$count = mysqli_num_rows($modal);
if ($count == "0") {
?>
<td class="text-center">NOT FOUND</td>
<?php
} else {
while ($defect = mysqli_fetch_array($modal)) {
?>
<tr>
<td class="text-center"><?php echo $defect['PROCESS_TIME']; ?></td>
<?php foreach ($_POST['chk'] as $id => $data) { ?>
<td class="text-center"><?php echo $defect[$data]; ?></td>
<?php } ?>
</tr>
<?php
}
}
}
?>
谢谢
解决方法:
在查看您的代码段时,我有几个安全性和效率方面的问题,但是要重点关注所提出的问题,问题似乎是您在$modal末尾流氓WHERE肯定会引起问题.
如果这样做不能减轻错误,则应改进您的问题,以包括所生成的确切错误消息.
而且我发现在GROUP BY子句中的第三个条件之前没有.
尽管我真的希望我可以在将代码段发布到此处之前对其进行测试,但是我认为脚本将提供更高的安全性,稳定性,效率和可读性. (当然,不能保证它没有错误)
<?php
if (empty($_POST['chk']
|| empty($_POST['start_date'])
|| empty($_POST['end_date'])
|| !is_array($_POST['chk'])
|| date('Y-m-d', strtotime($_POST['start_date'])) !== $_POST['start_date']
|| date('Y-m-d', strtotime($_POST['end_date'])) !== $_POST['end_date']) {
echo "Missing/Invalid Submission Data";
} else { // all expected submission data is present and sufficiently valid
$defect_select_ext = "";
foreach ($_POST['chk'] as &$data) {
$data = (int)$data; // for security
$defect_select_ext .= ", COUNT(CASE a.DEFECT_CLASS_ID WHEN $data THEN c.DEFECT_CLASS_NAME END) AS `$data`";
}
// I assume you are already connected...
// avoid iterated queries but maintain order
if (!$result = mysqli_query($mysqli, "SELECT DEFECT_CLASS_NAME FROM t_defect_class WHERE DEFECT_CLASS_ID IN (" . implode(',', $_POST['chk']) . ") ORDER BY FIELD(DEFECT_CLASS_ID," . implode(',', $_POST['chk']) . ")")) {
echo "Syntax Error While Retrieving DEFECT CLASS NAMES";
} else {
?>
<table>
<thead>
<tr>
<th class="text-center">Date Process</th>
<?php
while ($row = mysqli_fetch_assoc($result)) {
echo "<th class=\"text-center\">{$row['DEFECT_CLASS_NAME']}</th>";
}
?>
</tr>
</thead>
<tbody>
<?php
$query = "SELECT t_name_file.PROCESS_TIME" . $defect_select_ext . "
FROM t_transaction a
INNER JOIN t_name_file b ON a.NAMEFILE_ID = b.NAMEFILE_ID
INNER JOIN t_defect_class c ON a.DEFECT_CLASS_ID = c.DEFECT_CLASS_ID
GROUP BY a.DEFECT_CLASS_ID,
b.PROCESS_TIME,
b.PROCESS_TIME BETWEEN '$start_date' AND '$end_date'
ORDER BY t_name_file.PROCESS_TIME");
$colspan = sizeof($_POST['chk']) + 1;
if (!$modal = mysqli_query($mysqli, $query)) {
echo "<tr><td colspan=\"$colspan\" class=\"text-center\">Syntax Error @ Master Query</td></tr>";
} elseif (!mysqli_num_rows($modal)) {
echo "<tr><td colspan=\"$colspan\" class=\"text-center\">NOT FOUND</td></tr>";
} else {
while ($row = mysqli_fetch_array($modal)) {
echo "<tr>";
echo "<td class=\"text-center\">{$row['PROCESS_TIME']}</td>";
foreach ($_POST['chk'] as $data) {
echo "<td class=\"text-center\">{$row[$data]}</td>";
}
echo "</tr>";
}
}
echo "</table>";
}
}
ps.我建议您将数据库表名和列名都保留为小写,以便于将表/列名与MYSQL关键字/功能区分开来.
标签：mysqli,php 来源： https://codeday.me/bug/20191108/2008119.html
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