我有一些对象是由JAXB从XML文件解组的.是否有可能让JAXB告诉我或以某种方式找出每个对象来自XML文件(行和列)的位置?
此信息在某些时候可用,因为JAXB在架构验证错误期间将其提供给我.但我也希望它可用于经过验证的对象.
解决方法:
您可以通过利用XMLStreamReader和Unmarshaller.Listener在JAXB中执行此操作:
演示
package forum383861;
import java.io.FileInputStream;
import java.util.HashMap;
import java.util.Map;
import javax.xml.bind.JAXBContext;
import javax.xml.bind.Unmarshaller;
import javax.xml.bind.Unmarshaller.Listener;
import javax.xml.stream.Location;
import javax.xml.stream.XMLInputFactory;
import javax.xml.stream.XMLStreamReader;
public class Demo {
public static void main(String[] args) throws Exception {
JAXBContext jc = JAXBContext.newInstance(Customer.class);
XMLInputFactory xif = XMLInputFactory.newFactory();
FileInputStream xml = new FileInputStream("src/forum383861/input.xml");
XMLStreamReader xsr = xif.createXMLStreamReader(xml);
Unmarshaller unmarshaller = jc.createUnmarshaller();
LocationListener ll = new LocationListener(xsr);
unmarshaller.setListener(ll);
Customer customer = (Customer) unmarshaller.unmarshal(xsr);
System.out.println(ll.getLocation(customer));
System.out.println(ll.getLocation(customer.getAddress()));
}
private static class LocationListener extends Listener {
private XMLStreamReader xsr;
private Map<Object, Location> locations;
public LocationListener(XMLStreamReader xsr) {
this.xsr = xsr;
this.locations = new HashMap<Object, Location>();
}
@Override
public void beforeUnmarshal(Object target, Object parent) {
locations.put(target, xsr.getLocation());
}
public Location getLocation(Object o) {
return locations.get(o);
}
}
}
input.xml中
<?xml version="1.0" encoding="UTF-8"?>
<customer>
<address/>
</customer>
产量
[row,col {unknown-source}]: [2,1]
[row,col {unknown-source}]: [3,5]
顾客
package forum383861;
import javax.xml.bind.annotation.XmlRootElement;
@XmlRootElement
public class Customer {
private Address address;
public Address getAddress() {
return address;
}
public void setAddress(Address address) {
this.address = address;
}
}
地址
package forum383861;
public class Address {
}
欲获得更多信息
> http://blog.bdoughan.com/2011/08/using-unmarshallerlistener-to-capture.html
标签:java,jaxb 来源: https://codeday.me/bug/20191008/1870721.html
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