考虑以下xml:
<Config>
<Paths>
<Path reference="WS_License"/>
</Paths>
<Steps>
<Step id="WS_License" title="License Agreement" />
</Steps>
</Config>
以下JAXB类:
public class Path {
private String _reference;
public String getReference() {
return _reference;
}
@XmlAttribute
public void setReference( String reference ) {
_reference = reference;
}
}
和
public class Step {
private String _id;
private String _title;
public String getId() {
return _id;
}
@XmlAttribute
public void setId( String id ) {
_id = id;
}
public String getTitle() {
return _title;
}
@XmlAttribute
public void setTitle( String title ) {
_title = title;
}
}
我不想将引用作为String存储在Path对象中,而是将其作为Step对象保存.这些对象之间的链接是reference和id属性. @XMLJavaTypeAdapter属性是否可行?任何人都可以如此善良地提供正确用法的例子吗?
谢谢!
编辑:
我也想用元素做同样的技术.
考虑以下xml:
<Config>
<Step id="WS_License" title="License Agreement">
<DetailPanelReference reference="DP_License" />
</Step>
<DetailPanels>
<DetalPanel id="DP_License" title="License Agreement" />
</DetailPanels>
</Config>
以下JAXB类:
@XmlAccessorType(XmlAccessType.FIELD)
public class Step {
@XmlID
@XmlAttribute(name="id")
private String _id;
@XmlAttribute(name="title")
private String _title;
@XmlIDREF
@XmlElement(name="DetailPanelReference", type=DetailPanel.class)
private DetailPanel[] _detailPanels; //Doesn't seem to work
}
@XmlAccessorType(XmlAccessType.FIELD)
public class DetailPanel {
@XmlID
@XmlAttribute(name="id")
private String _id;
@XmlAttribute(name="title")
private String _title;
}
Step-object中的属性_detailPanels为空,链接似乎不起作用.是否有任何选项可以在不创建仅包含对DetailPanel的引用的新JAXB对象的情况下创建链接?
再次感谢 : )!
解决方法:
您可以使用@XmlID将属性映射为键,使用@XmlIDREF将引用映射到此用例的键.
步
@XmlAccessorType(XmlAccessType.FIELD)
public class Step {
@XmlID
@XmlAttribute
private String _id;
}
路径
@XmlAccessorType(XmlAccessType.FIELD)
public class Path {
@XmlIDREF
@XmlAttribute
private Step _reference;
}
欲获得更多信息
> http://blog.bdoughan.com/2010/10/jaxb-and-shared-references-xmlid-and.html
UPDATE
Thanks! I Completely missed your article. I’ve extended my question,
do you have any clue if this is possible too? I do not want to create
a class with only holding the reference, I’d like to store it inside
the step class.
注意:我是EclipseLink JAXB (MOXy)领导者,也是JAXB (JSR-222)专家组的成员.
如果您使用MOXy作为JAXB(JSR-222)提供程序,那么您可以将@XmlPath批注用于您的用例.
import javax.xml.bind.annotation.*;
import org.eclipse.persistence.oxm.annotations.XmlPath;
@XmlAccessorType(XmlAccessType.FIELD)
public class Step {
@XmlID
@XmlAttribute
private String id;
@XmlPath("DetailPanelReference/@reference")
@XmlIDREF
// private List<DetailPanel> _detailPanels; // WORKS
private DetailPanel[] _detailPanels; // See bug: http://bugs.eclipse.org/399293
}
欲获得更多信息
> http://bugs.eclipse.org/399293
> http://blog.bdoughan.com/2011/05/specifying-eclipselink-moxy-as-your.html
> http://blog.bdoughan.com/2010/07/xpath-based-mapping.html
标签:java,xml,jaxb 来源: https://codeday.me/bug/20190729/1569291.html
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