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LeetCode-76. Minimum Window Substring [C++][Java]

2022-02-10 00:00:13  阅读:188  来源: 互联网

标签:cnt minL string ++ C++ Substring minStart window Java


LeetCode-76. Minimum Window Substringhttps://leetcode.com/problems/minimum-window-substring/

题目描述

Given two strings s and t of lengths m and n respectively, return the minimum window substring of s such that every character in t (including duplicates) is included in the window. If there is no such substring, return the empty string "".

The testcases will be generated such that the answer is unique.

substring is a contiguous sequence of characters within the string.

Example 1:

Input: s = "ADOBECODEBANC", t = "ABC"
Output: "BANC"
Explanation: The minimum window substring "BANC" includes 'A', 'B', and 'C' from string t.

Example 2:

Input: s = "a", t = "a"
Output: "a"
Explanation: The entire string s is the minimum window.

Example 3:

Input: s = "a", t = "aa"
Output: ""
Explanation: Both 'a's from t must be included in the window.
Since the largest window of s only has one 'a', return empty string.

解题思路

【C++】

class Solution {
public:
    string minWindow(string s, string t) {
        vector<int> ch(256, 0);
        for(auto c : t) ch[c]++;
        int b=0, e=0, cnt=t.size(), minStart=0, minL=INT_MAX;
        while (e<s.size()) {
            if(ch[s[e++]]-- > 0) cnt--;
            while(cnt == 0) {
                if(e-b < minL) {minL=e-b; minStart=b;}
                if(ch[s[b++]]++ == 0) cnt++;
            }
        }
        return minL == INT_MAX ? "" : s.substr(minStart, minL);
    }
}

【Java】

class Solution {
    public String minWindow(String s, String t) {
        int[] ch = new int[256];
        for(char c : t.toCharArray()) ch[c]++;
        int b=0, e=0, cnt=t.length(), minStart=0, minL=Integer.MAX_VALUE;
        while (e<s.length()) {
            if(ch[s.charAt(e++)]-- > 0) cnt--;
            while(cnt == 0) {
                if(e-b < minL) {minL=e-b; minStart=b;}
                if(ch[s.charAt(b++)]++ == 0) cnt++;
            }
        }
        return minL == Integer.MAX_VALUE ? "" : s.substring(minStart, minStart + minL);
    }
}

参考文献

【1】leetcode刷题2———子串系列_taifyang的博客-CSDN博客

标签:cnt,minL,string,++,C++,Substring,minStart,window,Java
来源: https://blog.csdn.net/qq_15711195/article/details/122852073

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